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4 years ago

Find m<2 and m<3 in the rhombus. The diagram is not to scale.

Mathematics

1 answer:

Umnica [9.8K]4 years ago

5 0

Answer:

m∠2 = 118, and m∠3 = 31

Step-by-step explanation:

The 2 opposite angles of a rhombus are equal.

Angle 1 and Angle 2 are opposite to each other. Since Angle 1 is 118, angle 2 is also 118.

Now looking at the bottom triangle in the rhombus, the two sides are equal (given by 2 lines). Hence, the 2 opposite angles are equal. Since we know 3 angles of a triangle add up to 180 degrees, we can write: (let angle 3 be x):

x + x + 118 = 180

2x = 180 - 118

2x = 62

x = 62/2

x = 31

So m∠2 = 118, and m∠3 = 31

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2 (a - 5) - 5 = 3<br> Marking brainliest

tekilochka [14]

Answer:

Step-by-step explanation:

2a-10-15=3

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3 years ago

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Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

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3 years ago

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yulyashka [42]

First find X by subtracting 9.8 from 14.7
X should equal 4.9
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you then subtract in the parenthasis
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finally multiply 1.2x8
Your final answer is 9.6

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3 years ago

a baker wants to make 10 batches of cookie. each batch uses 2/3 cup.of sugar. how many cups of sugar will the baker need to make

Alchen [17]

Answer:

10 x 2/3 = 20/3 or 6 cups and 2/3

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3 years ago

X +5+11x=12x+Y It says find the value of y that makes each equation true for all values of

sladkih [1.3K]

X + 5 + 11x = 12x + y

Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)

Subtract 12x from each side makes each zero.

5 = y

So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82

x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
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x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989

So we verified y = 5

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3 years ago