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3 years ago

F(x) = (x^2 - 4) / √x F'(x) = ...?

1 answer:

fomenos3 years ago

6 0

$f(x)=\dfrac{x^2-4}{\sqrt{x}}\\\\f'(x)=\dfrac{(x^2-4)'(\sqrt{x})-(x^2-4)(\sqrt{x})'}{(\sqrt{x})^2}=\dfrac{2x\sqrt{x}-\dfrac{1}{2\sqrt{x}}(x^2-4)}{x}\\\\=\dfrac{\dfrac{2x\sqrt{x}\cdot2\sqrt{x}}{2\sqrt{x}}-\dfrac{x^2-4}{2\sqrt{x}}}{x}=\dfrac{4x^2-x^2+4}{2x\sqrt{x}}=\dfrac{3x^2+4}{2x\sqrt{x}}$

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riadik2000 [5.3K]

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Step-by-step explanation:

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4 years ago

A 40% sugar solution is added to an 85% sugar solution to create 1800 mL of a 60% solution. How much of each solution is used? (

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Answer:

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Number of ml of 85% sugar used = y = 800mL

Step-by-step explanation:

Let the

Number of ml of 40% sugar = x

Number of ml of 85% sugar used = y

From the above question, our system of equations is given as:

x + y = 1800mL ....... Equation 1

x = 1800 - y

40% × x + 85% × y = 60% × 1800mL

0.4x + 0.85y = 1080.... Equation 2

We substitute 1800 - y for x in Equation 2

0.4(1800 - y) + 0.85y = 1080

720 - 0.4y + 0.85y = 1080

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3 years ago