Answer:
D-both a relation and a function
Step-by-step explanation:
Answer:
A number times five is greater than fifteen. A number less negative seven is less than or equal to five. The difference between a number and seven is less than zero. The sum of a number and seven is greater than or equal to fifteen.
Answer:
1 inch to 4: 12 to 28
the second one: 8 to 128
The third one: 5 to 125
The fourth one: 13 to 117
Step-by-step explanation:
if that makes sense, I hope this will help
Answer: x = 4
Step-by-step explanation: To solve this equation, we could go right to our steps of subtracting 5.4 from both sides, but I would do a slightly different approach.
Since I hate working with decimals, I would get rid of them.
We can do this by multiplying both sides of the equation by 10, and remember to multiply every term by 10 to keep it balanced.
*Multiplying by 10 shifts the decimal point 1 place to the right
So we have 35x + 54 = 194 which looks a lot better.
Now subtract 54 from both sides to get 35x = 140.
Now divide both sides by 35 and x = 4.
Answer:
Option D) is correct
That is x=2 , y=-5
Step-by-step explanation:
Given that the ![|A|=\left| \begin{array}{cc}4&-6\\ 8&-2\end{array}\right|, \left|A_x\right|=\left|\begin{array}{cc}38&-6\\ 28&-2\end{array}\right|, \left|A_y\right|=\left|\begin{array}{cc}4&38\\ 8&26\end{array}\right|](https://tex.z-dn.net/?f=%7CA%7C%3D%5Cleft%7C%20%5Cbegin%7Barray%7D%7Bcc%7D4%26-6%5C%5C%208%26-2%5Cend%7Barray%7D%5Cright%7C%2C%20%5Cleft%7CA_x%5Cright%7C%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7D38%26-6%5C%5C%2028%26-2%5Cend%7Barray%7D%5Cright%7C%2C%20%5Cleft%7CA_y%5Cright%7C%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7D4%2638%5C%5C%208%2626%5Cend%7Barray%7D%5Cright%7C)
To find their determinants
![|A|=\left| \begin{array}{cc}4&-6\\ 8&-2\end{array}\right|](https://tex.z-dn.net/?f=%7CA%7C%3D%5Cleft%7C%20%5Cbegin%7Barray%7D%7Bcc%7D4%26-6%5C%5C%208%26-2%5Cend%7Barray%7D%5Cright%7C)
=-8+48
=40
Therefore ![|A|=40](https://tex.z-dn.net/?f=%7CA%7C%3D40)
![|A_x|=\left|\begin{array}{cc}38&-6\\ 28&-2\end{array}\right|](https://tex.z-dn.net/?f=%7CA_x%7C%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7D38%26-6%5C%5C%2028%26-2%5Cend%7Barray%7D%5Cright%7C)
=-76+156
=80
Therefore ![|A_x|=80](https://tex.z-dn.net/?f=%7CA_x%7C%3D80)
![|A_y|=\left|\begin{array}{cc}4&38\\ 8&26\end{array}\right|](https://tex.z-dn.net/?f=%7CA_y%7C%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7D4%2638%5C%5C%208%2626%5Cend%7Barray%7D%5Cright%7C)
=104-304
=-200
Therefore ![|A_y|=-200](https://tex.z-dn.net/?f=%7CA_y%7C%3D-200)
To find the values of x and y:
![x=\frac{|A_x|}{|A|}\ \textrm{and}\ y=\frac{|A_y|}{|A|}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%7CA_x%7C%7D%7B%7CA%7C%7D%5C%20%5Ctextrm%7Band%7D%5C%20y%3D%5Cfrac%7B%7CA_y%7C%7D%7B%7CA%7C%7D)
and ![y=\frac{-200}{40}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-200%7D%7B40%7D)
x=2 and y=-5
Option D) is correct
That is x=2 , y=-5