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Marysya12 [62]
3 years ago
14

Complete combustion of glucose (c6h12o6). oxygen gas is the other reactant in this combustion reaction. the products are co2 and

h2o
Chemistry
1 answer:
BartSMP [9]3 years ago
5 0
C6H12O6 +6O2 -----> 6CO2 + 6 H2O
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C. interior plains

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Which process releases the most heat?
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the boiling of 10g of liquid water

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The rate law for the decomposition of phosphine (PH3) is below. It takes 120. s for 1.00 M PH3 to decrease to 0.250 M. How much
Lubov Fominskaja [6]

Answer: 588.8 seconds

Explanation:

1.00 - 0.25 = 0.75M

4.00 - 0.320 = 3.68M

Therefore,

0.75M in 120 seconds

3.68M in x seconds

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0.75*x = 120*3.68

x = 120*3.68/0.75

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How much of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
Ivan

Answer: 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.05M\\V_2=25.0mL

Putting values in above equation, we get:

1\times 0.5\times V_1=1\times 0.05\times 25.0\\\\V_1=2.5mL

Thus 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

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