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Answer:
Butanoic Acid:
I have attached the structure of Butanoic Acid. Please refer to the attachment.
Explanation:
Solution:
First of all, we need to calculate the double bond equivalent (DBE) for the compound given:
Compound = C4H8O2
DBE = (C +1) - (H + X - N)/2
C = no. of carbons
H = no. of Hydrogen
X = no. of Halogens
N = no. of Nitrogen
DBE = (4+1) - (8/2)
DBE = 5-4
DBE = 1
It indicates the presence of 1 double bond in the possible structure.
Further structure can be identified by looking the peak values of the spectrum. So, we have,
2500 - 3300 = it indicates the presence of -COOH group
1720 = it indicates the (C=0) stretching
1200 = It indicates the (C-O) stretching
SO, the possible structure is
Butanoic Acid:
I have attached the structure of Butanoic Acid. Please refer to the attachment.
