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liberstina [14]
3 years ago
11

What type of foliation results from the parallel alignment of abundant, coarse-grained, mica flakes in a metamorphic rock?

Chemistry
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

Schistosity

Explanation:

Firstly, foliation is dominantly found in Metamorphic rocks and is said to be the parallel alignment of textural and structural features of rocks.

Differential stress is one major factor that contributes to the texture of metamorphic rocks. Differential stress can flattened the rocks constituents. Generally, planar texture rocks are said to be foliated.

Schistosity is a kind of foliation present in phyllite and Schist rocks that is characterize by coarse grained crystal due to the parallel alignment of platy minerals like mica, biotite and muscovite.

The picture above shows a schist rocks. The most visible way to recognize schistose texture is the visible platy minerals that depicts planar alignment.    

 

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A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO
Akimi4 [234]

Answer: The empirical formula for the given compound is CH_2

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=22.0g

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, \frac{12}{44}\times 22.0=6g of carbon will be contained.

For calculating the mass of hydrogen:

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Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = \frac{0.5}{0.5}=1

For Hydrogen  = \frac{1.0}{0.5}=2

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is C_{1}H_{2}=CH_2

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4 years ago
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sammy [17]

<u>Answer:</u>

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