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Effectus [21]
2 years ago
5

The actual density of iron is 7.874 g/mL. In a laboratory investigation, Jason finds the density of a piece of iron to be 7.921

g/mL.
What is the percent error that is associated with Jason’s measurement?
Chemistry
1 answer:
mixas84 [53]2 years ago
5 0

The percent error associated with Jason’s measurement is 0.596%.

HOW TO CALCULATE PERCENTAGE ERROR:

  • The percentage error of a measurement can be calculated by following the following process:
  1. Find the difference between the true value and the measured value of a quantity.
  2. Then, divide by the true value and then multiplied by 100

  • The true value of the density of iron is 7.874 g/mL
  • Jason observed value is 7.921 g/mL

Difference = 7.921 g/mL - 7.874 g/mL

Difference = 0.047 g/mL

Percentage error = 0.047/7.874 × 100

Percentage error = 0.596%.

Therefore, the percent error associated with Jason’s measurement is 0.596%.

Learn more: brainly.com/question/18074661?referrer=searchResults

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Another question please help!!! :)
Oxana [17]

The answer is [Boron]

I had this answer on my Chemistry test!

6 0
3 years ago
The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins
saul85 [17]
The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
So, we know:
t = 10 min
<span>t_{1/2} = 2.5 min

We need:
n = ?
x = ?
</span>
We could first use the second equation to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{10 min}{2.5 min}
⇒ n=4<span>
</span>
Now we can use the first equation to calculate the remained fraction of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^4
<span>⇒x= \frac{1}{16}</span>
3 0
3 years ago
What change in mass number occurs when a radioactive atom emits an alpha particle?
Alik [6]
The alpha particle is the helium nucleus.
The mass of helium nucleus (⁴₂He) is 4u.


The mass of radioactive atom decreases by 4u. Look at the reaction below:

²²³₈₈Ra ---> ⁴₂He + ²¹⁹₈₆Rn
6 0
3 years ago
What do you expect will occur as air masses move over cold locations? Hot locations? How does this movement of air masses affect
Maksim231197 [3]

Answer:

Explanation:

When air masses will move over cold location then bottom layer of air cools and become more dense. Due to its high density it is trapped near the ground then it flow towards the equator.

When it moves over hot location then bottom layer gets hot and lighter. Then it moves towards poles.

It changes the temperature and humidity of the climate. making hoter region coll and cooler region a bit hot.

3 0
3 years ago
In what ways can geographic position be considered a temperature control?
Lesechka [4]

Near water, change in elevation, or change in latitude.

4 0
3 years ago
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