Question

The actual density of iron is 7.874 g/mL. In a laboratory investigation, Jason finds the density of a piece of iron to be 7.921 g/mL.
What is the percent error that is associated with Jason’s measurement?

Answer 1

The percent error associated with Jason’s measurement is 0.596%.

HOW TO CALCULATE PERCENTAGE ERROR:

• The percentage error of a measurement can be calculated by following the following process:

1. Find the difference between the true value and the measured value of a quantity.
2. Then, divide by the true value and then multiplied by 100

• The true value of the density of iron is 7.874 g/mL
• Jason observed value is 7.921 g/mL

Difference = 7.921 g/mL - 7.874 g/mL

Difference = 0.047 g/mL

Percentage error = 0.047/7.874 × 100

Percentage error = 0.596%.

Therefore, the percent error associated with Jason’s measurement is 0.596%.

Learn more: brainly.com/question/18074661?referrer=searchResults