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Ganezh [65]
3 years ago
9

The age of water or wine may be determined by measuring its radioactive tritium(3H) content. Tritium, present in a steady state

in nature, is formed primarily by cosmicirradiation of water vapor in the upper atmosphere, and it decays spontaneously by a firstorder process with a half-life of 12.5 years. The formation reaction does not occursignificantly inside a glass bottle at the surface of the earth.Calculate the age of a suspected vintage wine that is 20 % as radioactive as a freshlybottled specimen.
Chemistry
1 answer:
notsponge [240]3 years ago
4 0

Answer: 29.0 years

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{12.5years}=0.0554years^{-1}

b) for decomposition of 80 % of reactant

t=\frac{2.303}{0.0554}\log\frac{100}{100-80}

t=\frac{2.303}{0.0554}\log\frac{100}{20}

t=29.0 years

The age of a suspected vintage wine that is 20 % as radioactive as a freshlybottled specimen is 29.0 years

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3 years ago
Two gases X and Y are found in the atmosphere in only trace amounts because they decompose quickly. When exposed to ultraviolet
igomit [66]

Answer:

1. Yes

2. After 68.1 mins, pX < pY.

Explanation:

Assuming the total gas pressure is 1 atm, let the partial pressure of Y be y, partial pressure of X will be 0.25y + y = 1.25y

1.25y + y = 1atm

2.25y = 1 atm

y = 1 atm / 2.25 = 0.44 atm

Then partial pressure of X = 0.56 atm

The partial pressure of a gas in a mixture of gases is directly proportional to the mole fraction of the gas.

Therefore the mole fraction of X and Y is 0.56 and 0.44 respectively.

The partial pressures of X and Y becomes half of their original values at 1.25 h = 85 min and Y at 150 min respectively.

The partial pressure after some time can be calculated from the half-life equation :

m = m⁰ *  1/2ⁿ

Where m = the remaining mass, m⁰ = initial mass, and n is number of half-lives undergone.

Let partial pressures represent the mass, and n for X and Y be a and b respectively:

pX  = 0.56/2ᵃ

pY = 0.44/2ᵇ

We then determine when Partial pressure of X, pX = Partial pressure of Y, pY

0.56/2ᵃ = 0.44/2ᵇ

2ᵃ/2ᵇ = 0.56/0.44

2ᵃ/2ᵇ = 1.27

2ᵃ⁻ᵇ = 2⁰°³⁴⁵

a - b = 0.345

Let this time be t, therefore,

For X; t = 85a and For Y: t = 150b

85a = 150b

then, a = 1.76b

1.76b - b = 0.345

0.760b = 0.345

b = 0.454 and,

a = 0.345 + 0.454 = 0.799

So,  X goes through 0.779 half-lives while Y goes through 0.454 half-lives Then, the time for both X and Y to have the same amount is:

t = 150 * 0.454 = 68.1 min

After 68.1 mins, pX < pY.

5 0
3 years ago
The thermometer in the picture reads, "19.9 degrees Celsius".
GalinKa [24]

Answer:

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Explanation:

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6 0
3 years ago
In going from room temperature 25° to 35 the rate of a reaction doubles calculate the activation energy for the reaction
Pepsi [2]

Answer:

52.9 KJmol-1

Explanation:

From;

log(k2/k1) = Ea/2.303 * R (1/T1 - 1/T2)

The temperatures must be converted to Kelvin;

T1 = 25° C + 273 = 298 K

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4 0
3 years ago
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sveta [45]

Answer:

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Explanation:

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D) CO₂(g) + H₂O(l) ⇒ H₂CO₃(aq). NO. All the elements keep the same oxidation numbers.

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