D.
Slope is rise over run and in this case it is -15/ 5 so when it is reduced you get -3 as your slope
The point that divides AB into a 3:2 ratio is calculated by (d) for a ratio of 3:2, divide AB into 5 equal parts. Each equal part is 2 units, so the point that divides AB into a 3:2 ratio is 2
<h3>How to determine the ratio?</h3>
The given parameters are:
A = -4
B = 6
Start by calculating the length AB using:
AB = |B - A|
This gives
AB = |6 -(-4)|
Evaluate
AB = 10
Next, the length is divided into 5 parts.
So, the length of each part is:
Length = 10/5
Length = 2
The point on the location 3 : 2 is then calculated as:
Point = A + 3 * Length
This gives
Point = -4 + 3 * 2
Evaluate
Point = 2
The above computation is represented by option (d)
Read more about number lines at:
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312 is the LCM for this set
Aside from the conventional formula for triangle, A=<span>½bh which is only applicable to problems where the base and height are already given and the triangle is a right triangle having a degree of 90. There are some formulas in getting the area of a triangle:
>Given three sides of the triangle, use Heron's Formula
A= sqrt(s(s-a)(s-b)(s-c))
s= (a+b+c)/2
>Given two sides with an included angle
</span>Area = <span>1/2 </span><span>ab sin (tetha)
</span><span>tethat should be in degrees
</span>
Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
Then we need to add together 66 and 25.13, which equals 91.13, or 91.1 to the nearest tenth.
I hope this helps!