Answer:
V₂ = 1.51L
Explanation:
According to Boyle's law:
P₁V₁ = P₂V₂
From the given parameter
P₁ = 153kPa
V₁ = 3.00L
P₂ =304kPa
V₂ = ?
Making V₂ the subject of the formula, we have:
V₂ = P₁ V₁/P₂
V₂ = 153 ₓ 3/304
V₂ = 1.51L
<span>___________ are formed at divergent and converging boundaries.
I think the answer is VOLCANOES
</span>
Answer:
b. is always a weak electrolyte.
Explanation:
Such compounds of low solubility dissociates partly and hence cannot be strong electrolytes
Answer:
1.346 v
Explanation:
1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:
(oxidation) → E°=0.337 v
(reduction) → E°=1.679 v
(overall) +8H^{+}_{(aq)}→ E°=1.342 v
2) Nernst Equation
Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:
Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.
The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give
E=1.346
The result will be no charge or neutral.. Because before losing an electron, the charge on ion was negative but after removal of 1 electron the charge is neutral.