The rate of increase of NH3 is 0.22M/s.
<h3>What is the balanced equation of the reaction?</h3>
The balanced equation of the reaction is given below:
- N2(g) + 3 H2(g) → 2 NH3(g)
The rate of decrease of N2 is half the rate of increase of NH3.
Rate of decrease of N2 = -0.11 M/s
Rate of increase of NH3 = 2 × +0.11 M/s = 0.22M/s.
In conclusion, the rate of formation of products is dependent on the rate of disappearance of reactants.
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The answer is (3) Cu2O. Copper (I) has an oxidation state of +1 (that's what the "I" indicates). You can also think of this as copper (I) having a charge of +1. Oxygen has an oxidation state of -2 (that's just a rule you have to know), and you can think of it as oxygen having a charge of -2. You need oxidation numbers in a neutral compound to add up to 0 (or charges in a neutral compond to add up to 0), so you need two Cu to balance the O, which is Cu2O.
