A)
Because it does not contain exactly all the DNA in the cell and some cells don't have a nucleus٫ such as the red blood cells.
Answer:
93.15 %
Explanation:
We have to start with the chemical reaction:
Now, we can balance the reaction:
Our initial data are the 15.71 g of 
, so we have to do the following steps:
1) <u>Convert from grams to moles of using the molar mass (110.98 g/mol).</u>
2) <u>Convert from moles of to moles of 
using the molar ratio. ( 1 mol = 1 mol of ).</u>
3) <u>Convert from moles of to grams of using the molar mass. (100 g/mol).</u>
Finally, we can calculate the yield percent:
I hope it helps!
Answer:
We will derive the combined gas equation from the law of Gases
Boyle's law
P∝1/V
PV=Constant
Charles law
V∝T
Avogadro's Law
V∝n
By combining these three equations we get the combined gas equation
PV=nRT
V=nRT/P
If n=1 mole
V=RT/P
By putting the value of R, T, and P in the above equation we can calculate the volume of the gas at STP.
Answer:
This question appear incomplete
Explanation:
This question appear incomplete because an equation to show the production of sodium chloride from calcium chloride should have been illustrated. However, if the balanced chemical equation showing sodium chloride (NaCl) been a product of a reaction involving calcium chloride (CaCl₂) as a reactant (shown below) is to be used, then we start by writing a complete balanced chemical equation
CaCl₂ + Na₂CO₃ ⇒ CaCO₃ + 2NaCl
From the equation above, it can be deduced that 1 mole of CaCl₂ is required to produce 2 moles of NaCl, thus how many moles of CaCl₂ will be required to produce 6.5 moles of NaCl.
1 mole of CaCl₂ = 2 moles of NaCl
? moles of CaCl₂ = 6.5 moles of NaCl
cross multiply
? moles of CaCl₂ = 6.5 × 1/2
? moles of CaCl₂ = 3.25 moles of CaCl₂
3.25 moles of CaCl₂ will be needed to produce 6.5 moles of NaCl
