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olchik [2.2K]
2 years ago
10

Look up and compare the ionic radii of In3+, Mn3+, and Y3+ for a specific coordination number. Why do you think Mn3+ forms a sol

id substitution on the In3+ rather than the Y3+ site?
Chemistry
1 answer:
Ainat [17]2 years ago
5 0

Answer:

See explanation

Explanation:

Substitution implies that one thing is repalced by the other.

Substitution of one ion by another largely depends on the sizes of the ions in question.

The ionic radius of Mn3+ is about 0.65 Angstroms while that of In3+ is about 0.94 Angstroms. On the other hand, the ionic radius of Y3+ is about 1.032 Angstroms.

It is clear that the sizes of Mn3+ and In3+ are closer to each other hence Mn3+ can substitute for In3+ easily than Y3+ in a lattice site.

The larger size of Y3+ explains why it is not easily replaced by Mn3+.

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How many carbon atoms are present in 0.46 moles of C2H6O?
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Number of atoms in 1 mole = 6.023 * 10²³
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In short, Your Answer would be Option B

Hope this helps!
3 0
3 years ago
When objects touch each other, charge can be transferred by
Dovator [93]

Answer:

friction

Explanation:

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and not just a riddle

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3 years ago
B. Which of the following compounds can
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The correct answer is:

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4 0
3 years ago
Read 2 more answers
A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0
2 years ago
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