1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kotegsom [21]
3 years ago
12

The ester below can be separated into phenol and an acetate salt, via saponification: heating the ester with a strong base, such

as sodium hydroxide, will produce phenol and sodium acetate. the two chemicals can then be separated by heat and filtration.
a. calculate the unsaturation number of the ester above.
b. calculate the molecular weight of the ester above

Chemistry
1 answer:
erastovalidia [21]3 years ago
4 0
I found a similar question online which will help me answer your incomplete question. To make it easier, show all the elements of the compound given. It is shown in the second picture attached.

a.) The formula for unsaturation number is shown in the 3rd picture attached. Following this, 
n = 8
m = 2(8) + 2 + 0 + 0 - 0 = 18
Thus,
x = Unsaturation number = (18 - 8)/2 = 5
<em>The unsaturation number is 5.</em>

b.) The molar mass of C is 12.01 g/mol; H is 1 g/mol; O is 16 g/mol. So, the molecular weight is:
Molecular weight = 12.01(8) + 8(1) + 2(16) = 136.08 g/mol
<em>The molecular weight of the ester is 136.08 g/mol.</em>

You might be interested in
Within each energy level there are different sublevels that are created. Those electrons that have the lowest
Volgvan
It’s option D cause we know that S orbital is spherical
4 0
2 years ago
A student performed a chemical reaction in which 35 grams of hydrogen and 65 grams of oxygen reacted to form water. What is the
sergejj [24]

Answer:

The mass of the product is 73,06 g

Explanation:

The reaction to form water is:

2H2 + O2 ---> 2H2O

35 g     65 g

Molar mass H2 = 2g/m ---> I have 17,5 moles (35g / 2 g/m)

Molar mass O2 = 32g/m ---> I have 2,03 moles (65g / 32g/m)

2 moles of H2 __reacts with __ 1 mol O2

17,5 moles of H2 __ reacts with ___ (17,5 m . 1 m) / 2 m = 8,75 m

I have just 2,03 m of O2 and I need 8,75 m so O2 is my limiting reagent

1 mol of O2 ___ reacts with 2 moles H2

2,03 moles of O2 __ reacts with  (2,03 m . 2 m) / 1 m = 4,06 m

I have 17,5 moles of H2 and I need 4,06 m. H2 is my excess reagent

<u><em>"All operations are done with the limiting reagent"</em></u>

1 mol O2 are required____ to form 2 H2O

2,03 mol O2 are required __ to form (2,03m . 2m) / 1m = 4,06 m

Molar mass of water: 18 g/m

Mass of water ----> Molar mass . Moles water = 18 g/m . 4,06 m = 73,08g

8 0
3 years ago
2. Balance the equation below, and answer the following question: What volume of chlorine gas, measured at STP, is needed to com
Juliette [100K]
Balanced equation: 2Na(s) + Cl₂(g) ---> 2NaCl(s)

when we have STP conditions, we can use this conversion: 1 mol = 22.4 L

first, we have to convert grams to molecules using the molar mass, and then use mole to mole ratio from the balanced equation. 

molar mass of Na= 23.0 g/mol
 ratio: 2 mol Na= 1 mol Cl₂ (based on coefficients of balanced equation)

calculations:

6.25 g Na ( \frac{1 mol Na}{23.0 g} ) ( \frac{1 mol Cl_2}{2 mol Na} ) ( \frac{22.4 L}{1 mol} )= 3.04 L
8 0
3 years ago
Insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. A bottle contains 375 mL of insu
Kitty [74]
Mass  =  Density  ×   Volume
          =  30.0 mg / mL  ×  375 mL
          =  11250 mg
          =  11.25 g

∴ the total mass of insulin in the bottle is 11.25 g (11250 mg)
4 0
3 years ago
How many grams of NaF should be added to 500 mL of a 0.100 M solution of HF to make a buffer with a pH of 3.2
Korolek [52]

Answer:

2.25g of NaF are needed to prepare the buffer of pH = 3.2

Explanation:

The mixture of a weak acid (HF) with its conjugate base (NaF), produce a buffer. To find the pH of a buffer we must use H-H equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer that you want = 3.2, pKa is the pKa of HF = 3.17, and [] could be taken as the moles of A-, the conjugate base (NaF) and the weak acid, HA, (HF). </em>

The moles of HF are:

500mL = 0.500L * (0.100mol/L) = 0.0500 moles HF

Replacing:

3.2 = 3.17 + log [A-] / [0.0500moles]

0.03 = log [A-] / [0.0500moles]

1.017152 = [A-] / [0.0500moles]

[A-] = 0.0500mol * 1.017152

[A-] = 0.0536 moles NaF

The mass could be obtained using the molar mass of NaF (41.99g/mol):

0.0536 moles NaF * (41.99g/mol) =

<h3>2.25g of NaF are needed to prepare the buffer of pH = 3.2</h3>
4 0
2 years ago
Other questions:
  • when 1.570 grams of the compound is vaporizedar 300 degrees celius and 1 atmosphere, the gas occupies a volume of 577 milliliter
    7·2 answers
  • Two friends are arguing about the structure of the universe. Caleb says that the universe is made of many galaxies that are made
    11·1 answer
  • What is carbon dioxide an example of?
    12·2 answers
  • A chemical reaction has two elements as reactants. Which type of reaction might occur
    14·1 answer
  • How much heat will be transferred when 0.54g of sulfur reacts with 0.54g of oxygen to produce sulfur trioxide according to the f
    9·1 answer
  • Please help me I’ll mark you the brainiest! Please do NOT answer if you don’t know it.
    8·1 answer
  • How is the kinetic energy of the particles of a substance affected during a phase change?
    14·2 answers
  • What kind of structure do the cations and anions in table salt form
    7·1 answer
  • What is a Bohr model?
    15·2 answers
  • How many moles of silver oxide (l) are needed to produce 4 moles of silver?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!