C10H22 is a compound which is the most soluble in CC14 because both are non-polar in nature.
<h3>Why polar solute soluble in polar solvent?</h3>
We know that like dissolve like which means that polar solutes only dissolve in polar solvent while on the other hand, non-polar solutes only dissolve in non-polar solvent.
So we can conclude that C10H22 is a compound which is the most soluble in CC14 because both are non-polar in nature.
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Answer:
63.02 g.
Explanation:
- Na reacts with Cl₂ according to the balanced equation:
<em>2Na + Cl₂ → 2NaCl,</em>
It is clear that 2 mole of Na react with 1 mole of Cl₂ to produce 2 moles of NaCl.
- Firstly, we need to calculate the no. of moles of Na and Cl₂:
no. of moles of Na = (mass/atomic mass) = (19.0 g/22.9897 g/mol) = 0.826 g.
no. of moles of Cl₂ = (mass/atomic mass) = (34.0 g/70.906 g/mol) = 0.48 g.
- From the stichiometry, Na reacts with Cl₂ with a molar ratio (2:1).
<em>So, 0.826 mol of Na "the limiting reactant" reacts completely with 0.413 mol of Cl₂ "left over reactant".</em>
The no. of moles of Cl₂ remained after the reaction = 0.48 mol - 0.413 mol = 0.067 mol.
∴ The mass of Cl₂ remained after the reaction = (no. of moles of Cl₂ remained after the reaction)(molar mass of Cl₂) = (0.067 mol)(70.906 g/mol) = 4.75 g.
- To get the no. of grams of produced NaCl:
<u><em>using cross multiplication:</em></u>
2 mol of Na produce → 2 mol of NaCl, from the stichiometry.
∴ 0.826 mol of Na produce → 0.826 mol of NaCl.
∴ The mass of NaCl produced after the reaction = (no. of moles of NaCl)(molar mass of NaCl) = (0.826 mol)(58.44 g/mol) = 48.27 g.
∴ The total weight of the glass vial containing the final product = the weight of the glass vial + the weight of the remaining Cl₂ + the weight of the produced NaCl = 10.0 g + 4.75 g + 48.27 g = 63.02 g.
Answer:
The answer to your question is b. Mg is being oxidized and c. Mg is the
reducing agent.
Explanation:
Reduction is the gain of electrons
Oxidation is the loss of electrons
Reducing agent is the element that oxidizes itself and reduces another element.
Oxidizing agent is the element the reduces itself and oxidizes another element.
In this reaction:
Magnesium loses electrons so it is being oxidized and it is the reducing agent.