Answer:
MJK & PJR = Unequal
LJP & NJR = Equal
KJR & MJP = Equal ? (not too sure with this one)
MJP & PJR = Unequal
KJL & LJM = Unequal
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
Answer:
This answer is A
Step-by-step explanation:
your welcome, im fast to answer
<span>x + y = 56
x = 4y
---
4y + y = 56
5y = 56
y = 10.4
x = 41.6</span>
Answer:
the first one should be -548
Step-by-step explanation:
plug in the values and you should get -30+7(-72-2).
