Answer:
The answer is 35.
Step-by-step explanation:
1 and 1/4 hours total. 2/3 was performed before lunch. You need to find how long he practiced after lunch. So first you need to find a common denominator (CD) because the denominators aren't the same. When you find the CD for 1 and 1/4 you need to make it an improper fraction (IF) because it's a mixed number. When you do that you get 5 multiplied by 3 and then 4 multiplied by 3 doing this is helping you find the CD of 5/4 which happens to equal 15/12. Next you do the same for 2/3 but this time you multiply 2 by 4 and then 3 by 4 and in this case 2/3 now equals 8/12. Now you can work with finding how much Allen performed after lunch. To find this you need to subtract 15/12-8/12 to find how long he performed after lunch when you do that you get 7/12 hours which is equal to 35 minutes.
Answer:
See explanation
Step-by-step explanation:
The given function is 
To create a table we choose some values of x and plug it into the function and solve for y.
When x=-1, 
When x=0 y=0+4
When x=1, y=4+1=5
When x=2, y=6
The table looks like;
x y
-1 3
0 4
1 5
2 6
The solution is 
Explanation:
The given expression is 
We need to determine the solution of the given expression.
The solution of the expression can be determined by dividing the terms.
Thus, we have,
Let us factor out the common term 
from the numerator.
Thus, we get,
Cancelling the common terms, we get,
Thus, the solution of the expression is
Answer:
7/16
Approximately 0.44
Step by step explanation:
For the 1st student to arrive before 2nd student,
* the probability that he(1st student)to arrive during 3/4 hrs = 3/4
*Then he(1st student) will need to wait for 1/4 hrs
*The probability that he(1st student) arrive during the last 1/4 hrs = 1/4
*Then he(1st student) waits for average of 1/8 hrs (1/4 + 1/4)=1/8
*The total time he(1st student) wait = (3/4 ×1/4) +(1/4× 1/8) = 7/32
*For 1st and 2nd student to meet, the 2nd student need to arrive when 1st student is still arround, therefore the probability that 2nd student arrives when 1st student is arround = 7/32
*If 2nd student arrives before 1st student, the probability that they would meet is 7/32
* Adding both together 7/32 + 7/32 = 7/16
ANSWER = 0.4375
=0.44
