Answer:
x intercepts: (-1,0) and (2.5,0)
It will be a minimum because the coeficcent for the degree is positive. The coordinates of the vertex are: (.75,-6.125)
To graph this I would first draw points on the vertex (.75,-6.125) and the x intercepts (-1,0) and (2.5,0). I would then simply just sketch a parabola that met all those points.
Step-by-step explanation:
Work Below (can clarify anything if needed)
4x^2 + 5xy - y^2 = 6
Implicitly differentiating both sides,
4(2x) + 5(x y' + y) - 2yy' = 0
where y' = dy/dx
8x + 5xy' +5y -2yy' = 0
combining y' terms
y' (5x-2y) +8x +5y = 0
y'(5x-2y) = -(8x+5y)
dy/dx = -(8x+5y)/(5x-2y)
or
dy/dx = (8x+5y)/(2y-5x)
Answer:
The z-score of 90 is 1.35
Step-by-step explanation:
The z-score is calculated using the formula:

From the question, it was given that the mean is

and the standard deviation is

and x=90.
We substitute the given values to obtain:


Answer:
Step-by-step explanation:
If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...
Anyways, the half angle identity for tangent is

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.
If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:
which simplifies a bit to
and a bit more to

Bring up the lower fraction and flip it to divide to get
which of course simplifies to
-3. Choice A.