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2 years ago

15

Please help with the second question

1 answer:

saul85 [17]2 years ago

8 0

Answer:

451,435,650

Step-by-step explanation:

mark brianliest plz :)

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Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.

LuckyWell [14K]

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle.

Opposite angles of a Quadrilateral are Supplementary.

$\therefore \: \angle A + \angle C = 180° \\ \therefore \:(2x + 3) \degree+ (2x + 1) \degree = 180° \\ \therefore \: (4x + 4) \degree = 180° \\ \therefore \: (4x + 4) = 180 \\ \therefore \: 4x = 180 - 4 \\ \therefore \: 4x = 176 \\ \therefore \: x = \frac{176}{4} \\ \therefore \: x = 44 \\ \\ m\angle A = (2x + 3) \degree \\ = (2 \times 44 + 3) \degree \\ = (88 + 3) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle A =91 \degree}} \\ \\ m\angle C = (2x + 1) \degree \\ = (2 \times 44 + 1) \degree \\ = (88 + 1) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle C=89\degree}} \\ \\ m\angle D= (x - 10) \degree \\ = (44 - 10) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle D =34\degree}} \\ \\ similarly \\ \\ \huge \red{ \boxed{ \therefore \: m\angle B = 146\degree}} \\ \\$

6 0

2 years ago

Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.

Tems11 [23]

Answer:

The area of the triangle is $\sqrt{3}$

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is = $\frac{1}{2}(base \times height)$

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE = $\sqrt{(0-1)^2 + (0-1)^2}$

DE = $\sqrt{(-1) ^2 + (-1)^2$

DE = $\sqrt{1+1}$

DE = $\sqrt{2}$

Base = $\sqrt{2}$

Height is DF

DF = $tan(60^{\circ}) \times DE$

DF = $\sqrt{3} \times DE$

DF = $\sqrt{3} \times\sqrt{2}$

Now, the area of the triangle is

= $\frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})$

= $\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})$

= $\frac{1}{2}(2\sqrt{3} )$

= $\sqrt{3}$

6 0

2 years ago

. Find the area of the shaded<br>region of the given figures:<br>5cm<br>5cm<br>15cm<br>20cm

Flauer [41]

5cm ahahhaa easy omg wr have

4 0

3 years ago

What is 12.125 as a fraction

yulyashka [42]

$12 \frac{1}{8}$

3 0

3 years ago

Please answer these 2 questions please!

Leno4ka [110]

Answer:

The 4th answer, at the bottom.

Step-by-step explanation:

The first answer is proportional, because y is equivalent to .5x.

The second answer is also proportional, because the ratios are equivalent.

The third answer is also proportional, because the line goes through the origin.

The fourth answer isn't proportional, because the ratios aren't equivalent.

5 0

3 years ago