3) A linear equation to represent this would be 205 = 10x + b
x is days passed, which is 10, and b is the original amount.
10 times 10 is 100, so we now have 205 = 100 + b
Subtract 100 from both sides to get 105 = b, which is the starting amount.
The rate of change is 10, however many cans brought per day.
4) So it appears that for every 5 minutes she frosts 4 cupcakes, which means the rate of change is 4/5 using rise over run.
Subtract 4 from 28 to get the starting amount 5 minutes earlier.
The starting amount of frosted cupcakes is 24.
5) Every 3 months he gets 9 more CDS. So, every month he gets 3 new CDs.
That means the slope is 3.
Subtract 9 from 18 to get the starting amount.
The starting amount of CDs is 9.
Hope this helps!
So, The Crayola Crayon company can make 2400 crayons in 4 minutes. In other words, every 4 minutes they can make 2400 crayons, right? So, in 15 minutes how many would they have made? Well, what we do is we divide 15 by 4 which is 3.75. Then we multiply the result, 3.75, by 2400. 3.75 * 9000. So, in 15 minutes, Crayola would have made 900 crayons!
4/2400 = 15/x
Step 1: Cross Multiply
4/2400 = 15/x
4 * x = (15) * (2400)
4x = 36000
Step 2: Divide both sides by 2
4x/4 = 36000/2
x = 9000
The answer is, 9000!!! :D
Answer:
8r⁶s³ - 5r⁵s⁴ + r⁴s⁵ + 5r³s⁶
Step-by-step explanation:
(8r⁶s³-9r⁵s⁴+3r⁴s⁵)-(2r⁴s⁵-5r³s⁶-4r⁵s⁴)
We need to combine like terms, take care the exponents of r and s
(8r⁶s³-9r⁵s⁴+3r⁴s⁵)-(2r⁴s⁵-5r³s⁶-4r⁵s⁴)
multiply the second parenthesis by -1
= 8r⁶s³-9r⁵s⁴+3r⁴s⁵-2r⁴s⁵+5r³s⁶+4r⁵s⁴
= 8r⁶s³ + (-9r⁵s⁴ + 4r⁵s⁴) + (3r⁴s⁵-2r⁴s⁵) + 5r³s⁶
= 8r⁶s³ - 5r⁵s⁴ + r⁴s⁵ + 5r³s⁶
Note: r⁶s³ is not like r³s⁶
Answer:
Step-by-step explanation:
We know that the system of equations
a
1
x+b
1
y=c
1
a
2
x+b
2
y=c
2
has infinitely many solutions, if
a
2
a
1
=
b
2
b
1
=
c
2
c
1
Here, a
1
=2,b
1
=3,c
1
=4,a
2
=k+2,b
2
=6,c
2
=3k+2.
Therefore, the given system of equations will have infinitely many solutions, if
k+2
2
=
6
3
=
3k+2
4
⇒
k+2
2
=
6
3
and
6
3
=
3k+2
4
⇒
k+2
2
=
2
1
and
2
1
=
3k+2
4
⇒k+2=4 and 3k+2=8
⇒k=2 and k=2
⇒k=2
Hence, the given system of equations will have infinitely many solutions, if k=2.
