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3 years ago

URGENT!!!

Mathematics

2 answers:

andriy [413]3 years ago

7 0

Answer:

4(2s − 1) = 7s + 12 ok so first were going to multiply 4 by 2s and 1 seperatly

8s - 4 = 7s + 12 now were going to put all the naked numbers and variable numbers on one side so we can classify each and count them and when doing that REMEMBER the symbol changes so if it was + 12 on the other side its going to be - 12 and the other way around, same thing with mutliplication and division.

-7s + 8s = 12 + 4 (see how the positives changes to negatives and negatives change to positives)

s = 16

~batmans wife dun dun dun....

skad [1K]3 years ago

3 0

We need to get the variable on one side (usually the left side) and all other constants (like numbers and certain symbols like $\pi$ ) on the opposite side of the variable (usually the right side).

4(2s - 1) = 7s + 12 // Our starting equation
8s - 4 = 7s + 12 // Distribute the 4 across the 2s and the -1
s - 4 = 12 // Subtract both sides by 7s
s = 16 // Add both sides by 4

The variable s is equal to 16.

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Which of the following is a solution to the equation 0=x^2-8x-13

adoni [48]

I would say "c".
Two solutions were found :
x =(8-√116)/2=4-√ 29 = -1.385
x =(8+√116)/2=4+√ 29 = 9.385

5 0

3 years ago

Factor completely x2 − 10x + 25. (2 points)

Arada [10]

Answer:

(x - 5)(x - 5)

Step-by-step explanation:

Given the expression

x^2 - 10x + 25

Look for the factors of x^2 and 25.

The factors are x and 5.

Therefore,

(x -5) (x-5)

When you distribute , you have

X x X - X x 5 - 5 x X - 5 x -5

x^2 -5x - 5x +25

x^2 - 10x + 25

4 0

4 years ago

MAT 171

steposvetlana [31]

Using the Factor Theorem, the polynomials are given as follows:

1. $P(x) = x^5 + 2x^4 - 7x^3 + x^2$

2. $P(x) = 0.8(x^4 - 4x^3 - 16x^2 + 64x)$

3. P(x) = -0.1(x³ - 4x² - 3x + 18)

<h3>What is the Factor Theorem?</h3>

The Factor Theorem states that a polynomial function with roots $x_1, x_2, \codts, x_n$ is given by:

$f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)$

In which a is the leading coefficient.

Item a:

The parameters are:

$a = 1, x_1 = x_2 = 1, x_3 = x_4 = 0, x_5 = -4$

Hence the equation is:

P(x) = (x - 1)²x²(x + 4)

P(x) = (x² - 2x + 1)(x + 4)x²

P(x) = (x³ + 2x² - 7x + 1)x²

$P(x) = x^5 + 2x^4 - 7x^3 + x^2$

Item b:

The roots are:

$x_1 = x_2 = 4, x_3 = 0, x_4 = -4$

Hence:

P(x) = a(x - 4)²x(x + 4)

P(x) = a(x² - 16)x(x - 4)

P(x) = a(x³ - 16x)(x - 4)

$P(x) = a(x^4 - 4x^3 - 16x^2 + 64x)$

It passes through the point x = 5, P(x) = 36, hence:

45a = 36.

a = 4/5

a = 0.8

Hence:

$P(x) = 0.8(x^4 - 4x^3 - 16x^2 + 64x)$

Item 3:

The roots are:

$x_1 = x_2 = 3, x_3 = -2$

Hence:

P(x) = a(x - 3)²(x + 2)

P(x) = a(x² - 6x + 9)(x + 2)

P(x) = a(x³ - 4x² - 3x + 18)

For the y-intercept, x = 0, y = -1.8, hence:

18a = -1.8 -> a = -0.1

Thus the function is:

P(x) = -0.1(x³ - 4x² - 3x + 18)

More can be learned about the Factor Theorem at brainly.com/question/24380382

#SPJ1

5 0

2 years ago

Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v

olga_2 [115]

We are given

$f=z^3 -x^2y$

Firstly, we can find gradient

so, we will find partial derivatives

$f_x=0 -2xy$

$f_x=-2xy$

$f_y=0 -x^2$

$f_y=-x^2$

$f_z=3z^2$

now, we can plug point (-5,5,2)

$f_x=-2*-5*5=50$

$f_y=-(-5)^2=-25$

$f_z=3(2)^2=12$

so, gradient will be

$gradf=(50,-25,12)$

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

$|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}$

$|v|=\sqrt{29}$

now, we can find unit vector

$v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

now, we can find dot product to find direction of the vector

$dir=(gradf) \cdot (v')$

now, we can plug values

$dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

$dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })$

$dir=-\frac{248\sqrt{29}}{29}$ .............Answer

7 0

4 years ago

Read 2 more answers

What is 3 square roots of 2

german

Answer:

Step-by-step explanation:

±3√2. Recall that 2 actually has two roots, one positive and the other negative.

4 0

3 years ago