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Fofino [41]
3 years ago
7

Complete the function table below for the function f(x) = 5x - 7

Mathematics
1 answer:
kati45 [8]3 years ago
3 0
1     2   3   4      5    6   
-2    3   8   13   18  23 
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W(x)=-3x-4 find w (7)
JulsSmile [24]

Answer:

w=-7

Step-by-step explanation:

Soooo-

W(x)=-3x-4

divide both sides by x

W=-3-4

combine like terms

W=-7

3 0
3 years ago
Read 2 more answers
Help me please thanks
Natalka [10]

Answer: All real numbers

Step-by-step explanation: If you plug in any number, it will work. 4(a+3) = 12+4a. a=-3  0=0


6 0
3 years ago
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A company buys pens at the rate of $5.50 per box for the first 10 boxes, $4.50 per box for the next 10 boxes, and $3.50 per box
marusya05 [52]

So it is really easy to solve firstly we can see how much does the first 10 boxes make which makes around 55$ obviously. Secondly 45$ for the next 10 boxes.

So for now we can simply calculate that we have spent around 100$ which means 20 boxes. The remaining money left is 77$ so we can buy 77/3.5 = 22 only 22 boxes with that money. Hence a total of 42 boxes.

4 0
3 years ago
Is (-5, 6) a solution to y = 2x + 4 ?<br> I need an answer quickly, please
Fittoniya [83]

Answer:

(-5, 6) is not a solution.

Step-by-step explanation:

6=2(-5)+4

6=-10+4

-10+4=-6, not 6.

7 0
3 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
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