Explanation:
We know that relation between and is as follows.
= 14
As it is given that is 8.18. Therefore, calculate the value of as follows.
= 14
= 14
= 14 - 8.18
= 5.82
Similarly, as value of pH is given as 7.18. Therefore, value of pOH will be as follows.
pH + pOH = 14
7.18 + pOH = 14
pOH = 6.82
Let us take that B represents the enzyme. Hence, its reaction with proton will be as follows.
(protonated active enzyme)
Hence, pOH =
6.82 = 5.82 +
= 10
Therefore, percentage of active enzyme = % =
% = 90.9%
Thus, we can conclude that 90.9% is the percentage of the enzyme which is active in a buffer at pH 7.18.