1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergio [31]
3 years ago
14

What other substance (besides salt) could you sprinkle over ice to affect how fast it melts? Describe how you would test the sub

stance's impact on the melting time of ice. Predict the results of such a test.
Chemistry
1 answer:
Georgia [21]3 years ago
7 0

Answer:

See explanation

Explanation:

Salt makes ice to melt faster than it usual. Sugar is another substance that influences the melting time of ice.

If i have a sample of pure ice and another sample of ice treated with sugar. I have to maintain the both initially at 0 degrees temperature and have a stop clock to measure the melting time.

I will ultimately notice that the sample of ice treated with sugar will melt faster than the pure sample of ice due to the presence of an impurity.

You might be interested in
An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined
e-lub [12.9K]

Answer:

6.68 X 10^-11

Explanation:

From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

The pH at the second equivalence point (8.181) will be the average of pKa2  and pKa3. So,

8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

7 0
3 years ago
Which of the following most accurately describes a regulatory molecule that must be transported to its place of action within th
Sonbull [250]

Answer:

the answer is hormone

Explanation:

because it is

5 0
2 years ago
What product has almost the same compounds as baking soda 10pts
mamaluj [8]
Ummm i actually dont know lol i swear i knew im sorry man or women ( im not trying to assume your gender 
4 0
3 years ago
Calculate the pH of 1.00 L of a buffer that contains 0.105 M HNO2 and 0.170 M NaNO2. What is the pH of the same buffer after the
kari74 [83]

Answer:

1.- pH =3.61

2.-pH =3.53

Explanation:

In the first part of this problem we can compute the pH of the buffer by making use of the Henderson-Hasselbach equation,

pH = pKa + log [A⁻]/[HA]

where [A⁻] is the conjugate base anion concentration ( [NO₂⁻]), [HA] is the weak acid concentration,[HNO₂].

In the second part, our strategy has to take into account that some of the weak base NO₂⁻ will be consumed by reaction with the very strong acid HCl. Thus, first we will calculate the new concentrations, and then find the new pH similar to the first part.

First Part

pH  = 3.40+ log {0.170 /0.105}

pH =  3.61

Second Part

# mol HCl = ( 0.001 L ) x 12.0 mol / L = 0.012

# mol NaNO₂ reacted = 0.012 mol ( 1: 1 reaction)

# mol NaNO₂ initial = 0.170 mol/L x 1 L = 0.170 mol

# mol NaNO₂ remaining = (0.170 - 0.012) mol  = 0.158

# mol HNO₂ produced = 0.012 mol

# mol HNO₂ initial = 0.105

# new mol HNO₂ = (0.105 + 0.012) mol = 0.117 mol

Now we are ready to use the Henderson-Hasselbach with the new ration. Notice that we dont have to calculate the concentration (M) since we are using a ratio.

pH = 3.40 + log {0.158/.0117}

pH = 3.53

Notice there is little variation in the pH of the buffer. That is the usefulness of buffers.

4 0
2 years ago
Read 2 more answers
If u (x) = negative 2 x squared and v (x) = StartFraction 1 Over x EndFraction, what is the range of (u circle ma poottay
KonstantinChe [14]
The range is negative numbers.
The interval for the range is .
***You might want to look at your functions again because I don't see a choice that matches.
Step-by-step explanation:
Given functions:


We are asked to find the range of .
I'm also going to look at the domain just to see if this possibly might change my range .
is the inner function. So we will consider the domain of that function first.
You only have to worry about division by zero for the function .
Since we are dividing by , we don't want to be zero.
So far the domain is all real numbers except .
Now let's move out.
exists for all numbers, . So we didn't want to include from before.
Now let's put it together:







So the domain is still all real numbers except at since we cannot divide by 0 and is 0 when .
with .
is positive for all numbers except .
So is negative for all numbers since negative divided by positive is negative.
So the range is only negative numbers.
Let's also look at the inverse:

Multiply both sides by :

Divide both sides by :

Take the square root of both sides:
.
So can't be 0 and it also can't be positive because the inside of the square root will be negative (since negative divided by positive results in negative).
5 0
3 years ago
Other questions:
  • Which of the following is a way of purifying water?
    6·1 answer
  • A solution of baking soda and water has a pH of 8.40. What type of solution is this?
    14·1 answer
  • Which of the following statements is/are true? I: The conjugate acid of C6H5NH2 is C6H5NH3+ II: An acid with Ka = 1x10−3 is stro
    11·1 answer
  • Sort the following chemicals for their ability to act as an oxidizer. List from strongest to weakest; 1 being strongest, 6 being
    11·2 answers
  • Which of the following represents the mass of 1 molecule of SH2?
    6·2 answers
  • If you drop a rubber ball covered in cooking sheet and fry it on a frying pan on hot temperature will it catch fire or will the
    12·1 answer
  • Marcus read that systems provide feedback, or the return of information. Feedback can either cause a change in the system or kee
    6·1 answer
  • Help please I will thank you
    8·1 answer
  • Name the following ester ch3c=ooch3
    5·1 answer
  • Plsssss helppppp asapppppppppp
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!