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2 years ago

Discuss the reason for the presence of large number of organic compounds

Chemistry

1 answer:

jeyben [28]2 years ago

4 0

Answer:

Carbon forms the large numbers of compound due to the following reasons

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In a titration, 10.0 ml of 0.0750 M HCl(aq) is exactly neutralized by 30.0 ml of KOH(aq) of unknown concentration. What is the c

Sphinxa [80]

Answer: 0.0250

Explanation: 10 X 0.0750 = .75

.75 / 30 = 0.0250 M

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3 years ago

If 2.65 mol of O2 gas has a volume of 49.0 L at 180 C, what is the pressure of the gas?

adoni [48]

Answer:

2.01atm

Explanation:

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2 years ago

Sort the examples based on whether they describe a physical change or a chemical reaction. growth of a seed into a seedling tarn

Pepsi [2]

Answer: I did the research myself since I couldn’t find the answers.

Physical change:

Wax melting from applied heat

Grinding wheat to make flour

Adding copper with gold to make jewelry

Chemical Reaction:

Growth of a seed into a seedling

Making caramel by burning sugar

Tarnishing of silver

Explanation:

Thanks google

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2 years ago

Which compounds represent the

Firlakuza [10]

Answer:

Both

compounds in left hand side of the equation is called reactants.

compounds in right hand side of the equation is called products.

so ans is both water and carbon di oxide

Explanation:

3 0

2 years ago

The enzyme, carbonic anhydrase, is a large zinc-containing protein with a molar mass of 3.00 x10^4 g/mol. Zn is 0.218% by mass o

tia_tia [17]

The mathematical expression for mass percent is given by:

$Mass percent = \frac{mass of the compound}{molar mass of the compound}\times 100$

Put the values,

$0.218 percent of zinc = \frac{mass of zinc}{3.00 \times 10^{4} g/mol}\times 100$

mass of zinc = $0.218 \times (3\times 100) g$

= $0.654 \times 100 g$ or 65.4 g

Now, number of moles of zinc = $\frac{given mass in g}{molar mass of zinc}$

= $\frac{65.4 g}{65.38 g/mol}$

= 1.00 mole

Number of atoms of zinc is calculated by the Avogadro number.

Now, according to mole concept

$6.022\times 10^{23}$ molecules of enzyme consists of $6.022\times 10^{23}$ atoms of zinc

So, 1 molecule of enzyme contains = $\frac{6.022\times 10^{23}atoms of zinc}{6.022\times 10^{23} }$

= 1 atom of zinc.

Hence, every carbonic anhydrase molecule consists of 1 atom of zinc.

5 0

3 years ago