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luda_lava [24]
4 years ago
10

¿Qué es un enlace químico?

Chemistry
1 answer:
fredd [130]4 years ago
4 0

Answer:

Un enlace químico es una atracción duradera entre átomos, iones o moléculas que permite la formación de compuestos químicos.

Explanation:

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Active, Dormant, and Extinct.
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Fill in the blanks. The celestial bodies in space move about in predictable paths called
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Answer:

The warmer, lighter air rises, bringing cooler, heavier air to low altitudes.

Air at higher altitudes doesn't have as much air weighing down on it from above.

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When 9.2 g of frozen N2O4 is added to a 0.50 L reaction vessel and the vessel is heated to 400 K and allowed to come to equilibr
Amanda [17]

<u>Answer:</u> The value of K_c for the given reaction is 1.435

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

Given mass of N_2O_4 = 9.2 g

Molar mass of N_2O_4 = 92 g/mol

Volume of solution = 0.50 L

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{9.2g}{92g/mol\times 0.50L}\\\\\text{Molarity of solution}=0.20M

For the given chemical equation:

                 N_2O_4(g)\rightleftharpoons 2NO_2(g)

<u>Initial:</u>          0.20

<u>At eqllm:</u>     0.20-x        2x

We are given:

Equilibrium concentration of N_2O_4 = 0.057

Evaluating the value of 'x'

\Rightarrow (0.20-x)=0.057\\\\\Rightarrow x=0.143

The expression of K_c for above equation follows:

K_c=\frac{[NO_2]^2}{[N_2O_4]}

[NO_2]_{eq}=2x=(2\times 0.143)=0.286M

[N_2O_4]_{eq}=0.057M

Putting values in above expression, we get:

K_c=\frac{(0.286)^2}{0.143}\\\\K_c=1.435

Hence, the value of K_c for the given reaction is 1.435

6 0
3 years ago
1. How many Chromium atoms are found in 25.8 milligrams of Chromium?​
givi [52]

Answer: 51.9961 g/mol, don't know if it helps :)

Explanation:

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