One term could be allostasis, the opposite of homeostasis.
Other antonyms of homeostasis, the body's ability to maintain a stable internal environment, include imbalance, instability, etc.
Methods Of Separating Mixtures
Handpicking.
Threshing.
Winnowing.
Sieving.
Evaporation.
Distillation.
Filtration or Sedimentation.
Separating Funnel.
Answer:
84.8 mL
Explanation:
From the question given above, the following data were obtained:
Mass of CuNO₃ = 3.53 g
Molarity of CuNO₃ = 0.330 M
Volume of solution =?
Next, we shall determine the number of mole in 3.53 g of CuNO₃. This can be obtained as follow:
Mass of CuNO₃ = 3.53 g
Molar mass of CuNO₃ = 63.5 + 14 + (16×3)
= 63.5 + 14 + 48
= 125.5 g/mol
Mole of CuNO₃ =?
Mole = mass / Molar mass
Mole of CuNO₃ = 3.53 / 125.5
Mole of CuNO₃ = 0.028 moles
Next, we shall determine the volume of the solution. This can be obtained as follow:
Molarity of CuNO₃ = 0.330 M
Mole of CuNO₃ = 0.028 moles
Volume of solution =?
Molarity = mole /Volume
0.330 = 0.028 / Volume
Cross multiply
0.330 × Volume = 0.028
Divide both side by 0.330
Volume = 0.028 / 0.330
Volume = 0.0848 L
Finally, we shall convert 0.0848 L to millilitres (mL). This can be obtained as follow:
1 L = 1000 mL
Therefore,
0.0848 L = 0.0848 L × 1000 mL / 1 L
0.0848 L = 84.8 mL
Therefore, the volume of the solution is 84.8 mL.
Volume of Hydrogen V1 = 351mL
Temperature T1 = 20 = 20 + 273 = 293 K
Temperature T2 = 38 = 38 + 273 = 311 K
We have V1 x T2 = V2 x T1
So V2 = (V1 x T2) / T1 = (351 x 311) / 293 = 372.56
Volume at 38 C = 373 ml
Answer:
390.85mL
Explanation:
Step 1:
Data obtained from the question.
Initial pressure (P1) = 780 torr
Initial volume (V1) = 400mL
Initial temperature (T1) = 40°C = 40°C + 273 = 313K
Final temperature (T2) = 25°C = 25°C + 273 = 298K
Final pressure (P2) = 1 atm = 760torr
Final volume (V2) =?
Step 2:
Determination of the final volume i.e the volume of the gas outside Matt's body.
The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:
P1V1/T1 = P2V2/T2
780 x 400/313 = 760 x V2 /298
Cross multiply to express in linear form
313 x 760 x V2 = 780 x 400 x 298
Divide both side by 313 x 760
V2 = (780 x 400 x 298) /(313 x 760)
V2 = 390.85mL
Therefore, the volume of the gas outside Matt's body is 390.85mL
