Answer:
B
explanation:
The car is not making a change in speed.
Circular acceleration has 2 components, the centripetal and tangential acceleration.
The formula for calculating the centripetal acceleration of a particle
is:
= v^2/r
Where v is the velocity or instantaneous speed and r is the radius.
= (3^2)/6 = 1.5 m/s^2
Assuming that the particle stays on the same circular path, another
thing it can have is the tangential acceleration. While the centripetal
acceleration is constant, tangential acceleration depends on the location of
the particle in the circular path. So to answer A and B, yes we can have an
acceleration of 6 and 4 respectively.
I couldnt type it out so here's a picture
Answer:
735.75 N
Explanation:
We are given;
Area of small lift; A1 = 5 cm²
Area of large lift; A2 = 300 cm²
Mass required to lift large lift;m = 4500 kg
Since Force = mg, then, Force required to lift large lift;F2 = 4500 × 9.81 = 44145 N
By Pascal's law,
F1/A1 = F2/A2
We want to find minimum force that must be applied to the small piston;F1, so let's make F1 the subject.
Thus;
F1 = (F2 × A1)/A2
Plugging in the relevant values, we have;
F1 = (44145 × 5)/300
F1 = 735.75 N