All categories

2 years ago

State the conservation of momentum theorem

Physics

1 answer:

Luda [366]2 years ago

7 0

Answer:

The total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

You might be interested in

The parallax method of measuring star distances gives most accurate results when the gap between two observations of a star is a

EleoNora [17]

<span>b. It ensures that measurements are taken from two points
that are very far apart.

Measurements taken six months apart are the farthest apart
that an astronomer can ever get ... they're on opposite sides
of the Earth's orbit !</span>

8 0

3 years ago

Read 2 more answers

Please help, I don't get this

Trava [24]

C the third one i think good luck

5 0

2 years ago

The sound source of a ship’s sonar system operates at a frequency of 22.0 kHz . The speed of sound in water (assumed to be at a

Degger [83]

Answer:

147.456077993 Hz

Explanation:

$f_0$ = Frequency of the sonar = 22 kHz

$v_w$ = Velocity of the whale = 4.95 m/s

v = Speed of sound in water = 1482 m/s

The difference in frequency is given by

$\Delta f=f_0\times\dfrac{2v_{w}}{v-v_w}\\\Rightarrow \Delta f=22000\times\dfrac{2\times 4.95}{1482-4.95}\\\Rightarrow \Delta f=147.456077993\ Hz$

The difference in frequency is 147.456077993 Hz

6 0

3 years ago

A truck speeds up from velocity of 6m/s to 14m/s in 4 seconds. what is the trucks acceleration?

Tanzania [10]

To calculate the acceleration of the truck, we use the equation of motion

$v = u + at$

Here, v is final velocity of the truck, u is initial velocity of truck, a is acceleration of the truck and t is time taken.

Given, u = 6 m/s, v = 14 m/s and t = 4 s.

Substituting these values in above equation, we get

$14 \ m/s = 6 \ m/s + a \times 4 \ s \\\\ a = \frac{14 \ m/s - 6 \ m/s}{ 4 \ s } = 2 \ m /s^2$ .

Thus, the truck acceleration is $2 \ m /s^2$

3 0

3 years ago

Consult Multiple-Concept Example 5 for insight into solving this problem. A skier slides horizontally along the snow for a dista

antoniya [11.8K]

The initial velocity of the skier is 4.5 m/s

Explanation:

There is only one force acting on the skier in the horizontal direction, and it is the force of friction, whose magnitude is

$F_f = -\mu_k mg$

where

$\mu_k = 0.050$ is the coefficient of kinetic friction

m is the mass of the skier

$g=9.8 m/s^2$ is the acceleration of gravity

The negative sign is due to the fact that the direction of the force of friction is opposite to the direction of motion of the skier.

According to Newton's second law, the net force acting on the skier is equal to the product between his mass and his acceleration, so we can write:

$F=ma\\ \rightarrow -\mu_k mg = ma$

So, the acceleration of the skier is

$a=-\mu_k g$

Now we can apply the following suvat equation to find the initial velocity of the skier:

$v^2-u^2=2as$

where

v = 0 is the final velocity (he comes to a stop)

u is the initial velocity

s = 21 m is the displacement

a is the acceleration

Substituting the equation for the acceleration and solving for u, we find

$u=\sqrt{v^2-2as}=\sqrt{-2(-\mu_k g) s}=\sqrt{2(0.050)(9.8)(21)}=4.5 m/s$

Learn more about accelerated motion here:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0

2 years ago