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Ludmilka [50]
3 years ago
15

How would you solve this? All I know is AD=24.4948

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

8

Step-by-step explanation:

Let's call the center of the middle circle J, and the center of the third circle K.

Draw a line from J to the line AD such that the line is perpendicular to AD.

This forms a right triangle that is similar to the triangle ΔADK.

Writing and solving a proportion:

x / DK = AJ / AK

x / 5 = 15 / 25

x = 3

Now, draw lines from J to B and C.  We now form two congruent right triangles, where the hypotenuse is 5 and the shared leg is 3.

That means these are both 3-4-5 triangles.

Therefore, BC = 4 + 4 = 8.

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Over [174]

Answer:

KM = 10.68; angle K= 55; angle M=35  

Step-by-step explanation:

Using Law of Cosine, you can find KM. Then using Law of Sines, you can find the angle of M. Find the sum of angle M and 90. Then subtract the total of that to 180 to fine angle K.  (sidenote: your angle K should be bigger then angle M since the side measurement of K is larger than M.)

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1. m∠QPR =<br><br> 2. m∠QTP =<br><br> 3. RP =<br> Show all the work
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Answer:

1. 30°

2.90°

3. 12 units

Step-by-step explanation:

I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)

1.

The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.

2.

If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.

3.

Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.

Sorry if this is all dreadfully wrong, and I hope I helped you!

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