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lana [24]
3 years ago
11

1)Simplify: 4d - 3e - 9d + 8e

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
5 0
Combine like terms:

-5d+5e or 5e-5d

If you want, you can factor out the common 5:

5(e-d) is your answer
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Davis is building a wooden bench. He has 2 3/5feet of lumber in his garage and buys 8 1/2feet of lumber at the store. How many t
Firdavs [7]

Answer:

Below.

Step-by-step explanation:

2 3/5 + 8 1/2

= 2 + 8  + 3/5 + 1/2

= 10 + 3/5 + 1/2

The LCM of 5 and 2 is 10 so we get:

10 + 6/10 + 5/10

= 10 + 11/10

= 10 + 1 1/10

= 11 1/10 feet.

8 0
3 years ago
What fraction of the word, "Supercalifragilisticexpialidocious" has the letter 'i' in it?
aniked [119]
I guess this is the LOL of the day. It's a very neat question. I had no idea how long that word was. I get 34 letters for the length of the whole word. Of the 34 letters, I thing there are 7 'i's. 

So the fraction is 7/34 <<<<====


5 0
3 years ago
Put the following in order from least to greatest 2.5, |-5|, -4, 15/-3
lidiya [134]
15/-3, -4, 2.5, |-5|
5 0
3 years ago
-2 (5) + 4 help plzzz
KengaRu [80]

Answer:

-6

Step-by-step explanation:

-2 * 5 = -10

-10 + 4 = -6

Answer is -6

3 0
3 years ago
Read 2 more answers
A graduate class consists of six students. What is the probability that at least 5 of them are born either in April or in Octobe
nlexa [21]

Answer:

0.0671% probability that at least 5 of them are born either in April or in October

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they were born in April or October, or they were not. The probabilty of a student being born in April or October is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of a student being born in April or October

April has 30 days, October 31

The year has 365 days. So

p = \frac{61}{365} = 0.167

A graduate class consists of six students.

This means that n = 6

What is the probability that at least 5 of them are born either in April or in October?

P(X \geq 5) = P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{6,5}.(0.167)^{5}.(0.833)^{1} = 0.000649

P(X = 6) = C_{6,6}.(0.167)^{6}.(0.833)^{0} = 0.000022

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.000649 + 0.000022 = 0.000671

0.0671% probability that at least 5 of them are born either in April or in October

8 0
3 years ago
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