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2 years ago

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A recipe for beef stew calls for 1 pound of beef and 3 potatoes the recipe is doubled to include 2 pounds of beef and 6 potatoes

which of the statements are true check all that apply

2 answers:

goblinko [34]2 years ago

6 0

Answer:

Step-by-step explanation:

Answer: (b)The numerators represent the pounds of beef. (d)The denominators represent the number of potatoes.

Lerok [7]2 years ago

4 0

Pounds of beef and potatoes are in ratio or proportion of $\frac{1}{3}$ .

<u>Step-by-step explanation:</u>

Correct Question: A recipe for beef stew calls for 1 pound of beef and 3 potatoes. The recipe is doubled to include 2 pounds of beef and 6 potatoes. Which proportion represents the situation?

We have , A recipe for beef stew calls for 1 pound of beef and 3 potatoes , i.e.

Number of beef stew calls = 1

Number of potatoes = 3

Now , The recipe is doubled to include 2 pounds of beef and 6 potatoes i.e. for every 2 pounds of beef we have 6 potatoes

⇒ $2/6$

⇒ $\frac{2}{6}$

⇒ $\frac{2}{2(3)}$

⇒ $\frac{1}{3}$

Therefore , Pounds of beef and potatoes are in ratio or proportion of $\frac{1}{3}$ .

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The average amount parents and children spent per child on back-to-school clothes in Autumn 2010 was $527. Assume the standard d

Ad libitum [116K]

Answer: a. 0.14085

b. 3.826 x $10^{-3}$

c. 0.5437

d. 0.0811

Step-by-step explanation:

Given average amount parents and children spent per child on back-to-school clothes in Autumn 2010 , $\mu$ = $527

Given standard deviation , $\sigma$ = $160

Let X = amount spent on a randomly selected child

Also Z = $\frac{X-\mu}{\sigma}$

a. Probability(X>$700) = P( $\frac{X-\mu}{\sigma}$ > $\frac{700-527}{160}$ ) = P(Z>1.08125) = 0.14085 {Using Z % table}

b. P(X<100) = P( Z < $\frac{100-527}{160}$ ) = P(Z< -2.66875) = P(Z > 2.66875) = 3.826 x $10^{-3}$

c. P(450<X<700) = P(X<700) - P(X<=450)

P(X<700) = 1 - P(X>=700) = 1 - 0.14085 = 0.8592

P(X<=450) = P(Z<= $\frac{450-527}{160}$ ) = P(Z<= -0.48125) = P(Z<=0.48125) = 0.3155

So final P(450<X<700) = 0.8592 - 0.3155 = 0.5437

d. P(X<=300) = P(Z<= $\frac{300-527}{160}$ ) = P(Z<= -1.4188) = P(Z>=1.4188) = 0.0811

All the above probabilities are calculated using Z % table along with interpolation between two values.

7 0

3 years ago

WORTH 50!! Answer it with explanation and the answer is not y+6 I have some idea on how to do this.

mafiozo [28]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx$

Where m =slope

We get

$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$m2=-\dfrac{3}{2}$

Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-7)=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

6 0

3 years ago

For a house call, a veterinarian charges $70, plus $40 an hour. Write an equation that represents the total fee y (in dollars) t

Svet_ta [14]

Y=40x+70

hope this helps

6 0

2 years ago

Read 2 more answers

If the eyepiece of a compound microscope has a magnification power of 10X and the objective lense has a magnification power of 4

aleksandrvk [35]

Answer:

Total magnification of microscope at this setting is 40X

Step-by-step explanation:

Total magnification of microscope is determined by multiplying the magnification power of individual lenses.

So if eyepiece has magnification power of 10X and objective lense has magnification power of 4X , the total magnification of microscope would be

10 × 4 = 40

which means the object will appear 40 times larger than actual object.

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3 years ago

the 41st term of the arithmetic sequence is -539 and the 54th term is -708. Find the value of the 80th term

yulyashka [42]

Answer:

$a _{n} = a _{1} + (n - 1)d \\ a _{41} = - 534 \\ a _{54} = - 708 \\ a _{41} = a _{1} + (41 - 1)d = - 534 \\ a _{1} + 40d = - 534 \: \: ...(1)\\ a _{54} = a _{1} + (54 - 1)d =- 708 \\ a _{1} + 53d = - 708 \: \: ...(2)$

Try to solve the similtanious equation to find the first term and the common difference, then use that information to figure out the 80th term... Update me if you need further help ...

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2 years ago