Answer:<BOC= 47
Step-by-step explanation:
Answer:
2.25 or 2 1/4 pounds
Step-by-step explanation:
We need to find the weight of the food and water. To do this, find the difference between his backpack before the food and water and after. His backpack without the food is 7 3/4 pounds, and his backpack after is 11 3/4 pounds.
11 3/4 - 7 3/4
4
The food and water together weigh 4 pounds. We know the water weighs 1 3/4 pounds, so we can subtract it from the total to find what the food weighs.
4- 1 3/4
2 1/4
As a decimal: 2.25
The food weighs 2 1/4 or 2.25 pounds
Answer:
![w=\frac{1}{2}m(v^2_2-v^2_1)](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B1%7D%7B2%7Dm%28v%5E2_2-v%5E2_1%29)
Step-by-step explanation:
We are given that a variable force of magnitude F(x) moves a body along the x- axis from
to
.
The net work done by the force in moving the body from
to
.
=Velocity of the body at ![x_1](https://tex.z-dn.net/?f=x_1)
Velocity of the body at ![x_2](https://tex.z-dn.net/?f=x_2)
We know that
Work done=Final kinetic energy-Initial kinetic energy
![w=\frac{1}{2}mv^2_2-\frac{1}{2}mv^2_1](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2_2-%5Cfrac%7B1%7D%7B2%7Dmv%5E2_1)
K.E=![\frac{1}{2}mv^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![Net\;work \;done=\frac{1}{2}m(v^2_2-v^2_1)](https://tex.z-dn.net/?f=Net%5C%3Bwork%20%5C%3Bdone%3D%5Cfrac%7B1%7D%7B2%7Dm%28v%5E2_2-v%5E2_1%29)
Hence, the net work done by the force is given by
![w=\frac{1}{2}m(v^2_2-v^2_1)](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B1%7D%7B2%7Dm%28v%5E2_2-v%5E2_1%29)
Answer:
= - 1/2
Step-by-step explanation:
6y+6.7=2.(y-3)
6y+42=2.(y-3)
6y+42=2y+2.-3
6y+42=2y-6
4y=-48
4y/4 = -48/4
y=-48/4
y=-12.4/1.4
y= -12
I believe the answer is C = 20