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Nutka1998 [239]
3 years ago
5

The diaper service where you work bills customers once a week. Each week, it charges 30¢ each for the first 75 diapers used, and

25¢ each for any additional diapers. How much should you bill a family that used 100 diapers last week?
A.

$18.75
B.

$22.50
C.

$25.00
D.

$28.75
E.

$30.00
Mathematics
1 answer:
maks197457 [2]3 years ago
5 0
The answer is 28.75
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Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

8 0
4 years ago
One week a computer store sold a total of 36 computers and external hard drives. the revenue from these sales was ​$30875 . if c
melamori03 [73]

To solve this problem you must apply the proccedure shown below:

1. You must make a system of equation by using the information given in the problem above. Then, let's call:

x: The number of computers sold.

y: The number of hard drives sold.

2. Therefore, you have the following system of equations:

\left \{ {{x+y=36} \atop {1180x+125y=30875}} \right.

2. Solve for x in the first equation and substitute it into the second equation:

x=36-y\\ 1180(36-y)+125y=30875

3. Solve for y:

42480-1180y+125y=30875\\ y=11

4. Substitute the value of y into the first equation to calculate x:

x+11=36\\ x=25

Therefore, the answer is: The store sold 25 computers and 11 hard drives.

5 0
3 years ago
Can someone explain this to me and how you do it. Also please help me get the answer and show some work on how you got it!
navik [9.2K]

Answer:

Step-by-step explanation:

5\frac{1}{3} ÷ \frac{4}{7} = \frac{16}{3} ÷ \frac{4}{7}

= \frac{16}{3} × \frac{4}{7}= \frac{64}{21}

3 0
3 years ago
How far will a train moveing at 42 miles ph travel in 31/2 hours?
PtichkaEL [24]

Answer:

651 i think

Step-by-step explanation:

31/2 =15.5 so 15.5 times 42 = 651


3 0
4 years ago
Read 2 more answers
Which of these data sets represents a function?
Elenna [48]

Answer:

It is B.

Step-by-step explanation:

No two same inputs or x are for the y.

3 0
3 years ago
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