Answer:
Charge, q = 900 C
Explanation:
It is given that,
Current flowing through the circuit, I = 6 A
Time for the flow of current, t = 2.5 minutes = 150 seconds
We have to find the charge delivered to this circuit. The total charge per unit time is called the current flowing through the circuit. It q is the charge flowing, then :
q = I × t
q = 6 A × 150 s
q = 900 coulomb
So, 900 coulomb of charge is delivered to this circuit.
Transverse wave
hope this helped a little at least
#3). Your drawing in the lower right corner is correct. You're headed down the right road, but ran out of gas and just stopped.
Radius of the circle = 1.5 km
Circumference of the whole circle = (2·π·radius) = 9.42 km
Distance = 3/4 of the way around it = 7.07 km .
Displacement = the straight line from the West point to the North point. The straight-line length is 2.12 km; the straight-line direction from start to finish is Northeast (45°). I'll let you figure out why these numbers.
#4). What if you walk 1 mile East and then 1 mile West ? You got a good workout, and you're back home where you started ! Your distance is 2 miles, and your displacement is zero.
The whale had a good workout too. She swam (6.9 + 1.8 + 3.7) = 12.4 km. She's sweating and tired. Her total distance during that workout is 12.4 km.
Her displacement is the line from start-point to end-point. How she got there doesn't matter, so swimming 1 km East and then swimming 1 km West cancel out, and have no effect on the displacement.
(6.9E + 1.8W + 3.7E) = (10.6 E) + (1.8 W) . . . That adds up to 8.8 East ! That's where she ends up. That's her displacement ... 8.8 km East of where she started. Since we're only talking about displacement, we don't care HOW she got there. She might have been swimming big 20-km circles all day. We don't know. All we know is that she ended up 8.8 km East of where she started.
Answer:
newton's third law of motion
Explanation:
The model of balloon car is example of newton's third law of motion which says that to every action there is always and equal and opposite reaction. As the balloon is inflated and then release the nozzle, the rubber contacts and pushes the air forward out of the nozzle, the air pushes back on the rubber and propelling the balloon forward.
Speed is the rate of change <span>of distance.</span>