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Juliette [100K]
3 years ago
14

A block of mass m=9.0 kg and speed V and is behind a block of mass M= 27 kg and speed of .50 m/s. The surface is frictionless, a

nd the blocks suddenly collide and couple. After the collision, the blocks have a common speed of .90 m/s. what was the speed v the lighter block before the collision'
Physics
1 answer:
sammy [17]3 years ago
5 0

Answer:

2.06 m/s

Explanation:

From the law of conservation of linear momentum, the sum of momentum before and after collision are equal. Considering this case where we have frictionless surface, no momentum is lost in the process.

Momentum before collision

Momentum is given by p=mv where m and v represent mass. The initial sum of momentum will be 9v+(27*0.5)=9v+13.5

Momentum after collision

The momentum after collision will be given by (9+27)*0.9=32.4

Relating the two then 9v+13.5=32.4

9v=18.5

V=2.055555555555555555555555555555555555555 m/s

Rounded off, v is approximately 2.06 m/s

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_____ replacement involves one element replacing another element in a compound.
Scorpion4ik [409]

Answer:

Single replacement

Explanation:

A single replacement reaction is a reaction in which the less reactive elements are replaced by the more reactive element in a compound. This is so because the more reactive element are higher in the electrochemical series element than the less reactive elements

3 0
3 years ago
For the long life cells we have to connect them in ____ combination​
NISA [10]

Answer:

Parallel combination.

5 0
3 years ago
Read 2 more answers
Si se aplic una fuerza de 150N en un área de de 0.4m2¿cual será la preciosa ejercida?
natali 33 [55]

Answer:

P = 375 Pa

Explanation:

The question says that,"If a force of 150N was applied in an area of ​​0.4m², what will be the precious exerted?"

We have,

Force, F = 150 N

Area, A = ​​0.4m²

We need to find the pressure exerted. We know that,

Pressure = forece/area

So,

P=\dfrac{150\ N}{0.4\ m^2}\\\\P=375\ Pa

So, the required pressure is equal to 375 pa.

7 0
3 years ago
A pendulum of length l=5.0m attached to the ceiling carries a ball of mass 10.0 kg. The ball (a massive bob) is moved from its s
never [62]

Answer:

    Em₀ = 245 J

Explanation:

We can solve this problem with the concepts of energy conservation, we assume that there is no friction with the air.

Initial energy the highest point

        Em₀ = U

        Em₀ = m g h

The height can be found with trigonometry

The length of the pendulum is L and the length for the angle of 60 ° is L ’, therefore the height from the lowest point is

         h = L - L’

         cos θ = L ’/ L

         L ’= L cos θ

          h = L (1 - cos θ)

We replace

         Em₀ = m g L (1- cos θ)

Let's calculate

         Em₀ = 10 9.8 5.0 (1 - cos 60)

         Em₀ = 245 J

3 0
3 years ago
A comet is a
Juli2301 [7.4K]
The answer is D. Small object made of ice and dust that orbits the Sun and forms a coma as it approaches the Sun.
7 0
3 years ago
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