Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so 
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So
Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Answer:
the first option
Step-by-step explanation:
2 angles are adjacent when:
They share a common vertex
and
they share a common side.
Answer:
24/25
Step-by-step explanation:
.96
the last digit is in the hundredths place so put it over 100
96/100
now we simplify
divide top and bottom by 4
24/25
Prime cost is the combination of a manufactured product's costs of direct materials and direct labor. In other words, prime cost refers to the direct production costs.
Prime cost=direct material cost+direct labor cost
Direct material cost of a tabletop is
380×(1÷4)=95 for each tabletop
Direct labor cost
The question says The machinist cuts and polishes five tabletops each hour
Which means 27.50 of direct labor to cut and polish 5 tabletops So direct labor cost for each tabletop is
27.50÷5=5.5
Finally the prime cost of cutting and polishing a tabletop is
Prime cost=95+5.5=100.5
(trying to isolate/get x by itself in the equation)
5(x + 6) = 50 Distributive property [distribute 5 into (x + 6)]
5x + 30 = 50 Subtraction [subtract 30 on both sides of the equation]
5x = 20 Division [divide 5 on both sides]
x = 4
Subtraction then division, the 2nd option
