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Write the function in vertex form y=x^2+6x+3
2 answers:
Answer:
y = 1(x + 3)² - 6
Step-by-step explanation:
The <em>standard form</em> of a quadratic function is
y = ax² + bx + c
The <em>vertex form</em> of a parabola is
y = a(x - h)² + k
where (h, k) is the <em>vertex</em> of the parabola.
h = -b/(2a) and k = f(h)
In the equation y= x² + 6x + 3
a = 1; b = 6; c = 3
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<em>Calculate h </em>
h = -6/(2×1)
h = -6/2
h = -3
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<em>Calculate k </em>
k = 1(-3)² + 6(-3) + 3
k = 9 - 18 +3
k = -6
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Write the <em>vertex form of the equation</em>
y = 1(x + 3)² - 6
The graph is a parabola with a vertex at (-3, -6).
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