Can you please help me because I can’t do it right

Mathematics

1 answer:

Dovator [93]3 years ago

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Enter the values for the variables that give the correct simplified expressions, x = ≥ 0.

ELEN [110]

Answer:

b= 2x²; c = 4; 3 = 3 ; g = 6x

Step-by-step explanation:

$\textbf{(1)}\\\sqrt{50{x}^{2} } = \sqrt{25\times2x^{2}} = 5\times \mathbf{\sqrt{2x^{2}}}\\\textbf{b = 2x}^{2}\\\\\textbf{(2)}\\\sqrt{32x} = \sqrt{16 \times 2x} = \mathbf{4}\times \sqrt{2x}\\\textbf{c = 4}\\\\\textbf{(3)}\\\sqrt{18n} = \sqrt{9 \times 2n} = \mathbf{3}\times \sqrt{2n}\\\textbf{e = 3}\\\\\textbf{(4)}\\\sqrt{72x^{2}} = \sqrt{36 \times 2x^{2}} = 6\times \sqrt{2} \times x\\= \mathbf{6x}\sqrt{2}\\\textbf{g = 6x}$

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3 years ago

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Help please, 30 points reward, i literally have no clue

Brums [2.3K]

The explanation for this is one of my favorite pieces of mathematical reasoning. First, let's thing about distance; what's the shortest distance between two points? A straight line. If we just drew a straight line between A and B, though, we'd be missing a crucial element of the original problem: we also need to pass through a point on the line (the "river"). Here's where the mathemagic comes in.

If we take the point B and reflect it over the line, creating the point B' (see picture 1), we can draw a line straight from A to B' that passes through a point on the line. Notice the symmetry here; the distance from the intersection point to B' is the same as its distance to B. So, if we reflect that segment back up, we'll have a path to B, and because it came from of the line segment AB', we know that it's the shortest possible distance that includes a point on the line.

If we apply this same process to our picture, we see that the line segment AB' crosses the line $\ell$ at the point (1, 1)