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GrogVix [38]
2 years ago
7

Which of the following statements is not true?

Mathematics
2 answers:
Thepotemich [5.8K]2 years ago
7 0

The above question is asking us to check if the exponents are written in the correct way or not.Let us look at the options one by one.

1) The exponent denotes the number of time the letter or number is multiplied.We have six x which are multiplied so the exponent for x which is 6 is right .The exponent is written correct .

2)We have seven A which are multiplied and five B multiplied making the exponent of A as 7 and B as 5 .The exponents are written correct.

3)There are six b and six c .The exponent rule has been followed here that is we can keep bc inside parenthesis and make 6 as the exponent.

4)Here exponent for x,y,z all are 5. we can not remove the exponent of x and y .It is not following the exponent rule .

Option 4 is not true.

Amiraneli [1.4K]2 years ago
4 0

The above question is asking us to check if the exponents are written in the correct way or not.Let us look at the options one by one.

1) The exponent denotes the number of time the letter or number is multiplied.We have six x which are multiplied so the exponent for x which is 6 is right .The exponent is written correct .

2)We have seven A which are multiplied and five B multiplied making the exponent of A as 7 and B as 5 .The exponents are written correct.

3)There are six b and six c .The exponent rule has been followed here that is we can keep bc inside parenthesis and make 6 as the exponent.

4)Here exponent for x,y,z all are 5. we can not remove the exponent of x and y .It is not following the exponent rule .

Option 4 is not true.

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Answer:

12

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Step-by-step explanation:

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3 years ago
A line passes through (7, -4) and (-3,4).<br><br>(NVM I FIGURED IT OUT)
Nonamiya [84]

Given :

Two points (7,-4) and (-3,4).

To Find :

The equation of line passes through the given points.

Solution :

We know, equation of line passing through two points (x₁, y₁) and (x₂, y₂) is given by :

y - y_1 = (\dfrac{y_2-y_1}{x_2-x_1})(x-x_1)\\\\y-(-4) = (\dfrac{4-(-4)}{-3-7})(x-7)\\\\y+4 = -\dfrac{4}{5}(x-7)\\\\5y+ 20 = -4x + 28\\\\5y + 4x = 8

Therefore, equation of required line is 5y + 4x = 8.

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2 years ago
I need help on this ASAP with work<br> 4 and 5
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The first is B and the second is H
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