Answer:
E.
Step-by-step explanation:
Translation: <u>s</u><u>l</u><u>i</u><u>d</u><u>e</u><u> </u>of the shape or figure, it does NOT change its shape, size, and form, count how many units the shape moves.
Reflection: <u>f</u><u>l</u><u>i</u><u>p</u> of the shape, does NOT change its shape, size, and form, either can be flipped or reflected over the x or y axis.
Rotation: <u>t</u><u>u</u><u>r</u><u>n</u> of the shape, does NOT change its shape, size, and form, either can be rotated counter clock wise left, (opposite of a clock direction), or clockwise, the direction a clock moves right. It can also be rotated 90° (1 turn), 180° (2 turns), 270° (3 turns) or 360° (4 turns). In highschool, you will get introduced to more degrees of rotation, this is just middle school level.
c is the correct answer to your problem
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
