Answer:
V₂ = 3227.46 L
Explanation:
Given data:
Initial volume of gas = 1000 L
Initial temperature = 50°C (50 +273 = 323 K)
Initial pressure = 101.3 KPa
Final pressure = 27.5 KPa
Final temperature = 10°C (10 +273 = 283 K)
Final volume = ?
Solution:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 101.3 KPa × 1000 L × 283 K / 323 K × 27.5 KPa
V₂ = 28667900 KPa .L. K /
8882.5 K.KPa
V₂ = 3227.46 L
The structure of Methanol (CH₃OH) is shown below. This structure contains
2 lone pair of electrons on oxygen (highlighted red). Electronic configuration of oxygen is,
Oxygen = 8 = 1s², 2s², 2px², 2py¹, 2pz¹
There are six electrons in valence shell of oxygen, among these six electrons two electrons are unpaired and involved in forming covalent bond with hydrogen and carbon, while remaining 4 electrons in pair (i.e. 2s², 2px²) exists as lone pairs.