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Kipish [7]
3 years ago
11

GIVING BRAINLIEST!!! A student observes a beaker of room temperature water resting on a table. She states that the beaker of wat

er does not have any energy. Which statement below is accurate regarding her observation?
a. She is correct because the beaker of water is not moving.


b. She is incorrect because the beaker of water has thermal energy.


c. She is incorrect because all water contains hydrogen and oxygen.


d. She is correct because the beaker of water is at room temperature.
Chemistry
2 answers:
defon3 years ago
8 0

Answer:

a

Explanation:

im thinking because the water is a room temperature there shouldnt be anm immence amount og heat energy for it to have a good amount of energy tho i could be wrong because its not moving it could have no energy.

AnnZ [28]3 years ago
5 0

Answer: please tell me i have this exact thing on a test rn i need the answer

Explanation:

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A 25.0 g block of a metal alloy at 100 C is dropped into an insulated flask containing 110 g of ice; 5.30 g of the ice melted. W
mr_godi [17]

Answer:

0.00353J/g/°C

Explanation:

I will assume the temperature of the ice to be approximately 0°C.

Moreover, Heat of fusion of water is 6kJ

Amount of heat used to melt 5.3g of ice = 5.3 x 6 / 18

=1.767g°C

Therefore

1.767 = 25 x specific heat cap. x 200

Specific heat cap. = 1.767/(25x200)

= 0.00353J/g/°C

6 0
3 years ago
A 251 ml sample of 0.45M HCl is added to 455 mL of distilled water. What is the molarity of the
Oksi-84 [34.3K]

<u>We are given:</u>

251 mL sample of 0.45M HCl added to 455 mL distilled water

<u>Whack a mole! (finding the number of moles):</u>

We know that in order to find molarity, we use the formula:

Molarity = number of moles / Volume (in L)

so, number of moles is:

Number of moles = Molarity * Volume(in L)

now let's plug the values for the HCl solution to find the number of moles

Number of moles = 0.45M * 0.251 L

Number of moles = 0.113 moles

<u>Time to concentrate (finding the final concentration):</u>

Total final volume = 251 mL + 455 mL = 706 mL = 0.706 L

Number of moles of HCl = 0.113 moles

Molarity = Number of moles / Volume (in L)

Molarity = 0.113 / 0.706

Molarity = 0.16 M

___________________________________________________________

<u>BONUS METHOD TIME!!!</u>

We know the relation:

M1 * V1 = M2 * V2

where M1 and M2 are the initial and final molarities and V1 and V2 are initial and final volumes respectively

notice that I didn't mention that the volume has to be in Liters, that's because of the units being concerned with both sides of the equation, say I have the volume in mL and want to convert both these volumes to L, I would divide both sides by 1000, which would NOT change the overall value

Now, plugging values in this equation

(0.45) * (251) = (251 + 455)* (M2)

112.95 = (706)(M2)

M2 = 112.97/706                                [dividing both sides by 706]

M2 = 0.16 Molar

8 0
2 years ago
Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t
Vitek1552 [10]

<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

Hence, the mass of decane produced is 1.743\times 10^2g

5 0
3 years ago
A 5 mole sample of liquid acetone is converted to a gas at 75.0°C. If 628 J are required to raise the temperature of the liquid
velikii [3]
The total energy required for this conversion is equivalent to the sum of the energies that are used. There are three steps:

1) Heating of liquid acetone
This used 628 J

2) Evaporation of acetone
This used 15.6 kJ or 15,600 J

3) Heating of acetone vapors
This used 712 J

Adding these quantities,

Total energy = 628 + 15,600 + 712

The total energy required was <span>16940 Joules of 16.94 kJ</span>
7 0
3 years ago
What volume of carbon dioxide gas at STP is required to produce 456.9g of lithium carbonate?
Margarita [4]

Answer:

It would have to be around 9.8 volume

Explanation:

7 0
3 years ago
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