The amount of W(OH)2 needed would be 448.126 g
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
W(OH)2 + 2 HCl → WCl2 + 2 H2O
The mole ratio of W(OH)2 to HCl is 1:2
Mole of 150g HCl = 150/36.461
= 4.11 moles
Equivalent mole of W(OH)2 = 4.11/2
= 2.06 moles
Mass of 2.06 moles W(OH)2 = 2.06 x 217.855
= 448.188g
More on stoichiometric calculations can be found here: brainly.com/question/8062886
Selenium (Se) the most common isotope of this element. The nucleus consists of 34 protons (red) and 46 neutrons (blue).
Answer : The concentration of 
is, 0.12 M
Explanation :
Using Henry's law :
where,
= concentration of = ?
= partial pressure of = 4.5 atm
= Henry's law constant = 
Now put all the given values in the above formula, we get:
Thus, the concentration of is, 0.12 M
An ionized has consisting of positive ions and free elections in proportion resulting in more or less no overall electric charge
