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galben [10]
2 years ago
10

What two atoms are held together by a covalent bond in NaHCO3

Chemistry
1 answer:
gtnhenbr [62]2 years ago
8 0

Answer: covalent bond is the force of attraction that holds together two atoms that share a pair of valence electrons. Covalent bonds form only between atoms of nonmetals. The two atoms that are held together in a covalent bond may be atoms of the same element or different elements.

Explanation:

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Alinara [238K]

Answer:

The answer to your question is No

Explanation:

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Also, I want to cook, all this process involves a lot of chemical reactions among the components of food and maybe water.

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Also, when I wash my clothes something similar happens.  

These are some examples of the chemical reactions that happen daily but I think there are a lot more.

5 0
3 years ago
Dalam kajian geografi, cara pandang dan cara pikir terhadap objek material dari sudut geografi disebut objek
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6 0
3 years ago
Your task is to create a buffered solution. You are provided with 0.10 M solutions of formic acid and sodium formate. Formic aci
Anton [14]

Answer:

15.2mL of the 0.10M sodium formate solution and 4.8mL of the 0.10M formic acid solution.

Explanation:

To find the pH of a buffer based on the concentration of the acid and conjugate base we must use Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where [A⁻] could be taken as moles of the sodium formate and [HA] moles of the formic acid</em>

<em />

4.25 = 3.75 + log [A⁻] / [HA]

0.5 = log [A⁻] / [HA]

3.162 = [A⁻] / [HA] <em>(1)</em>

<em></em>

As both solutions are 0.10M and you want to create 20mL of the buffer, the moles are:

0.10M  * 20x10⁻³L =

2x10⁻³moles = [A⁻] + [HA] <em>(2)</em>

Replacing (2) in (1):

3.162 = 2x10⁻³moles - [HA] / [HA]

3.162 [HA] = 2x10⁻³moles - [HA]

4.162[HA] = 2x10⁻³moles

[HA] = 4.805x10⁻⁴ moles

[A⁻] = 2x10⁻³moles - 4.805x10⁻⁴ moles = 1.5195x10⁻³moles

That means, to create the buffer you must add:

[A⁻] = 1.5195x10⁻³moles * (1L / 0.10mol) = 0.0152L =

<h3>15.2mL of the 0.10M sodium formate solution</h3>

[HA] = 4.805x10⁻⁴ moles * (1L / 0.10mol) = 0.0048L =

<h3>4.8mL of the 0.10M formic acid solution</h3>
4 0
3 years ago
How many moles are there in 135g of aluminum ?
dem82 [27]

Answer:

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