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Verdich [7]
3 years ago
5

A certain metal M forms a soluble sulfate salt M2SO4. Suppose the left half cell of a galvanic cell apparatus is filled with a 5

0.0 mM solution of M2SO4 and the right half cell with a 5.00 M solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them The temperature of the apparatus is held constant at 20.0 °C.
Which electrode will be positive?
What voltage will the voltmeter show?
Chemistry
1 answer:
quester [9]3 years ago
5 0

Answer:

Explanation:

For a certain metal M by which the electrodes and the solution M_2SO_4 the cell notation is:

                                    SALT BRIDGE

     ANODE                         ↓                    CATHODE

M(s)|M_2SO_4_{(aq)} (50.0 \ mM)\Big {|} \Big {|} M_2SO_4_{(aq)} (5.00 \ M ) |M(s)

Since the standard electrode potential is less positive on the left side, a negative anode electrode is used, and oxidation occurs at the anode.

i.e  \ \  M(s) \to M^{2+} _{(aq)} + 2 e^-  \ \ \  (oxidation)

The right side of the cell cathode is placed which is positive in sign and aids in reduction since the normal reduction potential is less negative.

i.e  \ \   M^{2+} _{(aq)} + 2 e^- \to M(s)   \ \ \  (reduction)

As a result, the correct answer for the positive electrode is the right side.

M_2SO_4 \to M^{2+} + SO_4^{2-}

Using Nernst Equation:

E_{cell} = - \dfrac{RT}{nF }log ( \dfrac{reduction \ half   }{oxidation \ half})

E_{cell} = - \dfrac{2.303 \times 8.314 \times 293}{2 \times 96485 }log ( \dfrac{5.0 0  }{50 \times 10^{-3}})

E_{cell} = -0.058 \ V

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Click the DeltaH is an Extensive Property button within the activity, and analyze the relationship between the two reactions tha
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Answer:

∴ΔH₂ = - 12,258 KJ

Explanation:

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Enthalpy is a property of a thermodynamic system. Enthalpy of a system is equal to the sum of internal energy of the system and presser times volume of the system.

    The heat absorbes or releases in a closed system is the change of enthalpy of the system.

Given reactions are:

Reaction 1: C₃H₈(g)+5O₂(g)→ 3CO₂(g)+4H₂O,                 ΔH₁= - 2043 KJ

Reaction 2: 6C₃H₈(g)+30 O₂(g)→ 18 CO₂(g)+24 H₂O,     ΔH₂=?

Take a look at reaction 1 and reaction 2, the only difference is that 1 molecule of C₃H₈ is combusted in reaction 1 and 6 molecules of C₃H₈  is  combusted in reaction 2.

We can think the reaction 2 as occurring 6 different container and each containers contains 1 molecule of C₃H₈. The enthalpy is an extensive property. Total enthapy of the 6 containers is = 6×(-2043 KJ)

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6 0
3 years ago
State the oxidation number of S in <br><img src="https://tex.z-dn.net/?f=H_%7B2%7DSO_%7B3%7D" id="TexFormula1" title="H_{2}SO_{3
Nezavi [6.7K]

Taking into account the definition of oxidation number, the oxidation numbers of S in H₂SO₃ is 4.

<h3>Definition of oxidation number</h3>

The oxidation number is the charge that an atom has; is an integer that represents the number of electrons an atom puts into play when it forms a given compound.

In other words, the oxidation number of an element is a value that indicates the number of electrons that element gains or loses when it combines with another.

<h3>Oxidation number determination</h3>

To determine the oxidation state of different elements it is necessary to know that:

  • The oxidation number of hydrogen in a compound is +1, except in metal hydrides, where is –1.
  • The oxidation number of oxygen in a compound is –2, except in peroxides, where it is –1.

On the other side, the sum of the oxidation numbers of the existing elements in a chemical formula must add up to zero.

Then, considering the oxidation numbers of each element, multiplying it by the number of existing elements in the chemical formula and adding it and equaling it to zero, the value of the missing oxidation number can be obtained.

<h3>Oxidation numbers of S</h3>

In this case, the oxidation numbers of S in H₂SO₃ is calculated as:

2× (+1) + oxidation numbers of S + 3×(-2)= 0

2 + oxidation numbers of S -6= 0

oxidation numbers of S -4= 0

<u><em>oxidation numbers of S= 4</em></u>

Finally, the oxidation numbers of S in H₂SO₃ is 4.

Learn more about the oxidation number:

brainly.com/question/8990767

brainly.com/question/6498977

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