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Bezzdna [24]
3 years ago
14

A recipe calls for 3 2/3 cups of flour. Earl used 7 1/3 cups. By how much did he increase the recipe

Mathematics
2 answers:
kolezko [41]3 years ago
8 0
3 2/3 =3.66
7 1/3 =7.33
7.33-3.66=3.77
Fynjy0 [20]3 years ago
6 0

Answer:

Earl doubled the number of recipies due to amount of flour.

Step-by-step explanation:

A recipe needs 3\,\frac{2}{3} cups of flour \left(\frac{11}{3}\right), whereas Earl made use of 7 \,\frac{1}{3} cups \left(\frac{22}{3}  \right). The number of equivalent recipies is determined by simple rule of three:

x = \frac{\frac{22}{3} }{\frac{11}{3} }

x = 2\,recipes

Earl doubled the number of recipies due to amount of flour.

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Answer:

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Step-by-step explanation:

Given

(x + 2y)² - (2x - y)² ← expand both parenthesis using FOIL

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= x² + 4xy + 4y² - 4x² + 4xy - y² ← collect like terms

= - 3x² + 8xy + 3y² ← factor out - 1 from each term

= - 1(3x² - 8xy - 3y²) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the coefficient of the y² term which sum to give the coefficient of the xy- term.

product = 3 × - 3 = - 9 and sum = - 8

The factors are - 9 and + 1

Use these factors to split the xy- term

3x² - 9xy + xy - 3y² ( factor the first/second and third/fourth terms )

= 3x(x - 3y) + y(x - 3y) ← factor out (x - 3y) from each term

= (x - 3y)(3x + y)

Thus

(x + 2y)² - (2x - y)² = - (x - 3y)(3x + y)

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4 years ago
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