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3 years ago

A recipe calls for 3 2/3 cups of flour. Earl used 7 1/3 cups. By how much did he increase the recipe

Mathematics

2 answers:

kolezko [41]3 years ago

8 0

3 2/3 =3.66
7 1/3 =7.33
7.33-3.66=3.77

Fynjy0 [20]3 years ago

6 0

Answer:

Earl doubled the number of recipies due to amount of flour.

Step-by-step explanation:

A recipe needs $3\,\frac{2}{3}$ cups of flour $\left(\frac{11}{3}\right)$ , whereas Earl made use of $7 \,\frac{1}{3}$ cups $\left(\frac{22}{3} \right)$ . The number of equivalent recipies is determined by simple rule of three:

$x = \frac{\frac{22}{3} }{\frac{11}{3} }$

$x = 2\,recipes$

Earl doubled the number of recipies due to amount of flour.

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One environmental group did a study of recycling habits in a California community. It found that 75% of the aluminum cans sold i

AysviL [449]

Answer:

$P( \^ p > 0.775 ) = 0.12798$

$P( 0.6718 < p < 0.775 ) =0.87183$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.75$

Considering question a

The sample size is $n = 387$

Generally the standard deviation of this sampling distribution is

$\sigma = \sqrt{ \frac{p(1 - p)}{ n } }$

=> $\sigma = \sqrt{ \frac{0.75(1 - 0.75)}{ 387 } }$

=> $\sigma = 0.022$

The sample proportion of cans that are recycled is

$\^ p = \frac{ 300}{387 }$

=> $\^ p = 0.775$

Generally the probability that 300 or more will be recycled is mathematically represented as

$P( \^ p > 0.775 ) = P( \frac{\^ p - p }{ \sigma } > \frac{0.775 - 0.75 }{ 0.022} )$

$\frac{\^ p - p }{\sigma } = Z (The \ standardized \ value\ of \ \^ p )$

$P( \^ p > 0.775 ) = P( Z > 1.136 )$

From the z table the area under the normal curve to the left corresponding to 1.591 is

$P( Z > 1.136) = 0.12798$

=> $P( \^ p > 0.775 ) = 0.12798$

Considering question b

Generally the lower limit of sample proportion of cans that are recycled is

$\^ p_1 = \frac{ 260 }{387 }$

=> $\^ p_1 = 0.6718$

Generally the upper limit of sample proportion of cans that are recycled is

$\^ p_2 = \frac{ 300}{387 }$

=> $\^ p_2 = 0.775$

Generally probability that between 260 and 300 will be recycled is mathematically represented as

$P( 0.6718 < p < 0.775 ) = P( \frac{0.6718 - 0.75 }{ 0.022}< \frac{\^ p - p }{ \sigma }$

=> $P( 0.6718 < p < 0.775 ) = P( -3.55 < Z < 1.136 )$

=> $P( 0.6718 < p < 0.775 ) = P(Z < 1.136 ) - P( Z < -3.55 )$

From the z table the area under the normal curve to the left corresponding to 1.136 and -3.55 is

$P( Z < -3.55 ) = 0.00019262$

and

$P(Z < 1.136 ) = 0.87202$

$P( 0.6718 < p < 0.775 ) = 0.87202- 0.00019262$

=> $P( 0.6718 < p < 0.775 ) =0.87183$

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2 years ago

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Answer by JKismyhusbandbae: expression 2 and expression 1

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Since expression 2 can be simplified to expression 1, they are equivalent.

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3 years ago

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const2013 [10]

Answer:

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Step-by-step explanation:

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2 years ago

Work out the value of<br> 5^8 x 5^-2 /<br> 5^4

IrinaK [193]

Answer:

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Step-by-step explanation:

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3 years ago

Determine whether the points (–3,–2) and (3,2) are in the solution set of the system of inequalities below. y ≤ ½x + 2 y < –2

lana [24]

Given:

The system of inequalities:

$y\leq \dfrac{1}{2}x+2$

$y$

To find:

Whether the points (–3,–2) and (3,2) are in the solution set of the given system of inequalities.

Solution:

A point is in the solution set of the given system of inequalities if it satisfies both inequalities.

Check for the point (-3,-2).

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$-2\leq -1.5+2$

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This statement is true.

$-2$

This statement is also true.

Since the point (-3,-2) satisfies both inequalities, therefore (-3,-2) is in the solution set of the given system of inequalities.

Now, check for the point (3,2).

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