Fun, geometry disguised as probability.
That's a pentagon, which we can view as 10 right triangles with legs a and s/2 (half of s) and hypotenuse r. So area of the pentagon is
P = 10 × (1/2) a (s/2) = 10 (1/2) (3.2) (4.7/2) = 37.6
The area of the circle is πr² so the circle area is
C = π (4²) = 50.265482
The white area is the difference, C-P, and the probability we seek is the fraction of the circle that's white, so (C-P)/C.
p = (C-P)/C =1-P/C = 1-37.6/50.265482 = 0.251971
Answer: 0.25
Higher than I would have guessed from the figure.
Answer:
3x² + x - 3
Step-by-step explanation:
The way I like to do it is to get rid of the x's and just use the numbers in the case of synthetic division
Pretend the square root of the division symbol
-4 √ 3 12 1 -12
Quick note: We're dividing by -4 because we're dividing by x + 4
First bring down the 3
-4 √ 3 13 1 -12
3
Multiply it by 4 then bring add it to the next number
-4 √ 3 13 1 -12
-12
3 1
Add that number to the next one
-4 √ 3 13 1 -12
-12 -4
3 1 -3
Finally repeat the step for the last number
-4 √ 3 13 1 -12
3 -12 -4 +12
3 1 -3 0
Now take those bottom numbers and add back the x's but with one less power, so the starting x³ would now become x², x² would become x, and so on
3x² + 1x - 3
X^2 = 9x + 6
x^2 - 9x - 6 = 0
use quadratic formula : (-b (+-) sqrt b^2 - 4ac) / (2a)
a = 1, b = -9, c = -6
now we sub
x = (-(-9) (+-) sqrt -9^2 - 4(1)(-6)) / 2(1)
x = 9 (+-) sqrt 81 + 24)/2
x = 9 (+-) sqrt 105) / 2
x = 9/2 + 1/2 sqrt 105 or x = 9/2 - 1/2 sqrt 105
It Is True . For A Function Each Input Should Only Have One OutPut .
Example ❤️ :
Input | Output
01 | 05
02. | 08
03. | 06
It Wouldn't Be A Function If The Input Had Repeated
Example ❤️ :
Input | Output
07. | 03
09. | 01
09. | 12
03. | 02
Answer:
x = 15
Therefore, the length and width are 31 and 47.
Step-by-step explanation:
Perimeter = (2x + 1) + (2x + 1) + (3x + 2) + (3x + 2) = 156
Simplified,
10x + 6 = 156
Subtract 6 from both sides, then divide by 10.
10x = 150
x = 15
To find the length and width, substitute 15 (the value of x) into the individual equations.
2(15) + 1 = 31
3(15) + 2 = 47
