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Alex17521 [72]
4 years ago
12

Arthur is performing a lab which requires a 0.2 M solution of calcium hydroxide. However, the only calcium hydroxide solution av

ailable has a concentration of 0.5 M. How can Arthur dilute the 0.5 M solution to make 10 mL of a 0.2 M solution?
Chemistry
1 answer:
aev [14]4 years ago
7 0

Answer:

He needs to add 4 mL of the 0.5 M solution to 6 mL of water.

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In a chemical reaction, __________ are the substances present after the reaction.
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Calcium Carbonate decomposes at 1200°C to form carbon dioxide and
Travka [436]

This is a Charles' Law problem: V1/T1 = V2/T2. As the temperature of a fixed mass of gas decreases at a constant pressure, the volume of the gas should also decrease proportionally.

To use Charles' Law, the temperature must be in Kelvin (x °C = x + 273.15 K). We want to solve Charles' Law for V2, which we can obtain by rearranging the equation into V2 = V1T2/T1. Given V1 = 25 L, T1 = 1200 °C (1473.15 K), and T2 = 25 °C (298.15 K):

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3. How many grams of aluminum can be heated from 90°C to 120°C if 500 J of heat energy are applied?
IgorLugansk [536]

<u>We are given:</u>

Initial Temperature = 90°c

Final Temperature = 120°c

Heat applied(ΔH) = 500 Joules

Specific heat(c) = 0.9 Joules / g°C

Mass of Aluminium(m) = ?

<u>Change in temperature:</u>

ΔT = Final temp. - Inital Temp.

ΔT = 120 - 90

ΔT = 30°c

<u>Calculating the mass:</u>

We know the formula:

ΔH = mcΔT

replacing the values:

500 = m(0.9)(30)

500 = m(27)

m = 500/27

m = 18.52 grams

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3 years ago
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