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Pavel [41]
3 years ago
14

Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K

elly ran at an average speed of 8 miles per hour. When will Ava and Kelly be 3/4 mile apart?
Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

Ava and Kelly will be 3/4 mile apart after 0.375 hours.

<h2>Why?</h2>

To calculate when will Ava and Kelly be 3/4 mile apart, we need to write the equations for both Ava's and Kelly's positions.

Writing the equations we have:

For Ava:

x_A=x_o+v_ot\\\\x_A=0+v_o*t\\\\x_A=v_{o(ava)*t

For Kelly:

We need to calculate when Kelly will be 3/4 mile apart becase is running faster than Ava, so, writing the equation we have:

x_K=x_A+\frac{3}{4}mile=x_o+v_{o(Kelly)}*t

Now, substituting the equation for Ava into the equation for Kelly, we have:

x_A+\frac{3}{4}mile=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+\frac{3}{4}mile}=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+0.75mile}=x_{o}+v_{o(Kelly)}*t\\\\6mph*t+0.75mile=8mph*t\\\\0.75mile=2mph*t\\\\t=\frac{0.75miles}{2mph}=0.375hours

To prove  that the result is correct, we just need to substitute the obtained value for time into both equations, so, substutiting we have:

For Ava:

x_A=v_{o(ava)*t=6mph*0.375hours=2.25miles

For Kelly:

x_K=v_{o(Kelly)}*t=8mph*0.375=3miles

There is a difference of 0.75 miles or 3/4 mile between Ava and Kelly, so, the obtained value for time is correct.

Therefore, we have that Ava and Kelly will be 3/4 mile apart after 0.375 hours.

Have a nice day!

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$18.24 (C)

Step-by-step explanation:

15.20 x 0.20 = 3.04

3.04 + 15.20 = 18.24

Hope this helped!

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What is the degree of the monomial 3x2y3
iVinArrow [24]

Answer:

Step-by-step explanation:

The degree of polynomial is the sum of exponents of the variables involved in the expression,hence the given degree is

2+3=5,so 5 is the degree of the polynomial.

4 0
3 years ago
The Math Club is raising money so they can attend a local competition next month. They have already raised $125 and they are sel
prisoha [69]

Answer: 100 candy bars

Step-by-step explanation:

You did not include the question but judging by the progression I can assume that the question is along the lines of how many candy bars they will need to sell to reach their target.

You did not include the amount they have to raise as well so let us assume that number is $375.

Assuming they have to raise $375 and they have already raised $125, the amount left to be raised is:

= 375 - 125

= $250

With each candy bar selling at $2.50, the number of candy bars they will need to sell is:

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<em>You should use this process to find the answer to your question. </em>

3 0
3 years ago
Look at the rectangle and the square:
Anettt [7]

Ada is <u>incorrect</u>, as the length of diagonal SQ is not two times the length of diagonal OM. The theorem used is the Pythagoras Theorem.

For Rectangle PQRS:-

By Pythagoras Theorem, in right triangle PQS,

SQ² = PQ² + PS²,

or, SQ² = 8² + 16² sq. inches,

or, SQ² = 64 + 256 sq. inches,

or, SQ = √320 sq. inches,

or, SQ = 8√5 inches.

Thus, the length of diagonal SQ, of rectangle PQRS is 8√5 inches.

For Square LMNO:-

By Pythagoras Theorem, in right triangle LMO,

OM² = LM² + LO²,

or, OM² = 8² + 8² sq. inches,

or, OM² = 64 + 64 sq. inches,

or, OM = √128 sq. inches,

or, OM = 8√2 inches.

Thus, the length of diagonal OM, of square LMNO is 8√2 inches.

We know that 2*OM ≠ SQ, as 2*8√2 ≈ 8√5.

Thus, Ada is <u>incorrect</u>, as the length of diagonal SQ is not two times the length of diagonal OM. The theorem used is the Pythagoras Theorem.

Learn more about the diagonal of square and rectangle at

brainly.com/question/22078692

#SPJ4

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2 years ago
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