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Vesna [10]
3 years ago
15

A 4,000 kg boat floats with one-third of its volume submerged. if two more people get into the boat, each of whom weighs 690 n,

what additional volume of water is displaced?
Physics
1 answer:
AveGali [126]3 years ago
4 0

 

The weightiness of the added water displaced is equivalent to the joined weight of the two extra people who come to be into the boat:


<span>m water g                   = 2 x 690 N</span>

<span>                                   = 1,380 N</span>

<span>
</span>

The mass of the water displace is then


<span>m water g                   = 1,380 N</span>

<span>                                   = 1,380 N / 9.8 m/s^2</span>

<span>                                   = 141 kg</span>

<span>
</span>

Compute the calculation for density for the volume of water displace and practice this outcome for the mass of the water displace to get the answer:


<span>p water                      = mass of water / volume of water</span>

<span>
</span>

<span>volume of water        = mass of water / p water</span>

<span>                                  = 141 kg / 1000 kg /m^3 eliminate kilogram</span>

<span>                                  = 0.14 m^3 the additional volume of water that is displaced</span>

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At a depth of 1030 m in Lake Baikal (a fresh water lake in Siberia), the pressure has increased by 100 atmospheres (to about 107
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\Delta V = 0.004\,m^{3}

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