All categories

3 years ago

What is the basis for rutherford's planetary model?

1 answer:

3 0

The basis for Rutherford's Planetary model, was the results he got from experiments.

He observed that most of the alpha particles he fired at a gold foil, passed through the foil, but only few were deflected back. So he concluded that most of the Atom would be empty space, with a positive entity at the center.

You might be interested in

A plane opens a parachute after it lands inorder to

Elis [28]

Answer:

When the parachute opens, the air resistance increases. The skydiver slows down until a new, lower terminal velocity is reached.

8 0

3 years ago

Read 2 more answers

Demuestre que la función de onda: y(x, t) = A e^−i(kx−ωt+φ) satisface la ecuación de onda lineal. (donde i =√−1).

Alekssandra [29.7K]

Answer:

La ecuación de onda lineal para una función f(x, t) se escribe como:

$\frac{d^2f}{dt^2} = c^2*\frac{d^2f}{dx^2}$

Donde c es una constante que depende de la velocidad de propagación de la onda.

En este caso, tenemos:

$f(x) = A*e^{-i*(k*x - w*t + \phi)}$

Recordar que la derivada de la exponente es tal que:

$k(x,y) = A*e^{c*x + n*y}\\dk/dx = c*A*e^{c*x + n*y}$

Entonces las derivadas de f van a ser:

$\frac{df}{dt} = (i*w)*f(x)$

$\frac{d^2f}{dt^2} = (i*w)^2*f(x) = -(w)^2*f(x)$

$\frac{df}{dx} = (-i*k)*f(x)$

$\frac{d^2f}{dx^2} = (-i*k)^2*f(x) = -k^2*f(x)$

Entonces podemos reescribir la ecuación de onda como:

$\frac{d^2f}{dt^2} = c^2*\frac{d^2f}{dx^2}$

$-(w)^2*f(x) = c^2*(-k^2*f(x))$

Ahora podemos simplemente definir c^2 = (w/k)^2 y vemos que la ecuación de onda se cumple.

5 0

3 years ago

Initial velocity=3m/s, final velocity=5m/s, displacement=2m. Find the acceleration.

shusha [124]

Answer:

Explanation:

To analyze the behavior of black bears during the night. To describe how black bears adapt to life near human. To evaluate the decline in the number of black bear.

4 0

3 years ago

Read 2 more answers

The rate at which an object moves

sergejj [24]

The rate at which an object moves is called speed or velocity depending if the direction does or doesnt matter

3 0

3 years ago

Read 2 more answers

When the force on an object and the object’s displacement are in different directions, which component of the force does work?

podryga [215]

Answer: