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Sergeu [11.5K]
3 years ago
7

What is the basis for rutherford's planetary model?

Physics
1 answer:
Olenka [21]3 years ago
3 0
The basis for Rutherford's Planetary model, was the results he got from experiments.

He observed that most of the alpha particles he fired at a gold foil, passed through the foil, but only few were deflected back. So he concluded that most of the Atom would be empty space, with a positive entity at the center.
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How do you find the net force acting on an object?
weqwewe [10]

Answer:

C. Add all the force vectors

Explanation:

The net force acting on an object is the vector sum of all the  forces on the object.

Remember, Newton's first law tells us a body at rest will remain at rest or that in uniform motion will continue in motion unless acted by unbalanced forces.These unbalanced forces act in all direction towards the body thus to get the net force you require a summation of all these force with respect to their magnitudes and directions.

For example a force of 3N towards the East direction acting on a body and another force of 2N towards the West direction on the same body will generate a net force of 1N towards the East direction.

4 0
4 years ago
Neuroticism, psychoticism, and extraversion are the three dominant personality traits according to
Anna71 [15]

The answer is b I just took the test

6 0
3 years ago
Read 2 more answers
sandra lives in a country located in the northern hemisphere she makes a sundial by erecting a pole vertically in her garden the
Arte-miy333 [17]

Answer:

C

Explanation:

The sun has rotated causing the shadow to reflect.

5 0
3 years ago
Explain a situation in which you can accelerate even thought your speed doesn’t change
Juli2301 [7.4K]

Explanation:

An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes. ... Light's acceleration is zero. Since it travels in a straight line, its direction does not change.

7 0
3 years ago
A 60kg skateboarder starts up a 20° slope at 5m/s then falls and slides up the hill on his knee pads. The coefficient of kinetic
klasskru [66]
2.0 meters  The skateboarder has 2 forces acting upon him to slow him down. The forces are friction, and climbing against the gravitational acceleration. So let's calculate the magnitude of these forces to see how fast he's decelerated.  The coefficient of kinetic friction is a multiplier to use against the normal force of the object. We can calculate the normal force by multiplying the mass of the object by the local gravitational acceleration and the cosine of the angle. So Df = 60 kg * 9.8 m/s^2 * cos(20°) * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 165.7617783 kg*m/s^2 Df = 165.7617783 N  
The second amount of force is that caused by gravitational acceleration while climbing. That is determine by the amount of height gained for every meter along the slope. We can calculate that using the sine of the angle. So 
Dg = 60 kg * 9.8 m/s^2 * sin(20°)
 Dg = 60 kg * 9.8 m/s^2 * 0.342020143
 Dg = 201.1078443 kg*m/s^2
 Dg = 201.1078443 N
 
 So the amount of force decelerating the skateboarder is:
 F = Df + Dg
 F = 165.7617783 N + 201.1078443 N
 F = 366.8696226 N
 
 Now let's determine how much kinetic energy needs to be dissipated. The equation is
 E = 0.5 MV^2 
 So we'll substitute the known values and calculate
 E = 0.5 MV^2
 E = 0.5* 60 kg * (5 m/s)^2
 E = 0.5* 60 kg * 25 m^2/s^2
 E = 750 kg*m^2/s^2
 E = 750 J 
 Now let's divide the energy by the force.
 750 kg*m^2/s^2 / 366.8696226 kg*m/s^2 = 2.04432298 m
  Rounding to 2 significant figures gives a distance of 2.0 meters.
4 0
3 years ago
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