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3 years ago

Can you hit the monkey at a fast speed with gravity on?

Physics

1 answer:

Ierofanga [76]3 years ago

7 0

Answer:

It depends how far the monkey is and how hard you throw the object because If the monkey is close, then you will most likely hit it

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Which of the following, by scientific definition is NOT work? lifting boxes of books, pedaling on your bike, holding a book over

Karolina [17]

Answer:

holding a book over your head

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3 years ago

Help help hep help???????????

Sergeu [11.5K]

Momentum

mava + mbvb = mava '+ mbvb'

(300 x 10)+(150 x 0) = (300 x 4.12)+(150 x vb')

3000=1236+150vb'

1764 = 150vb'

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2 years ago

A 2.0 kg 2.0kg2, point, 0, start text, k, g, end text cart moving right at 5.0 m s 5.0 s m 5, point, 0, start fraction, st

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Yes así le tienes que hacer para aprender

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3 years ago

Read 2 more answers

A heat engine operating between energy reservoirs at 20?c and 600?c has 30% of the maximum possible efficiency.

Anarel [89]

<span>The maximum possible efficiency, i.e the efficiency of a Carnot engine , is give by the ratio of the absolute temperatures of hot and cold reservoir.
η_max = 1 - (T_c/T_h)

For this engine:
η_max = 1 - [ (20 +273)K/(600 + 273)K ] = 0.66 = 66%

The actual efficiency of the engine is 30%, i.e.
η = 0.3 ∙ 0.664 = 0.20 = 20 %

On the other hand thermal efficiency is defined as the ratio of work done to the amount of heat absorbed from hot reservoir:
η = W/Q_h

So the heat required from hot reservoir is:
Q_h = W/η = 1000J / 0.20 = 5000J</span>

8 0

3 years ago

A stuntwoman is going to attempt a jump across a canyon that is 77 m wide. The ramp on the far side of the canyon is 25 m lower

liq [111]

initial speed of the stuntman is given as

$v = 28 m/s$

angle of inclination is given as

$\theta = 15 degree$

now the components of the velocity is given as

$v_x = 28 cos15 = 27.04 m/s$

$v_y = 28 sin15 = 7.25 m/s$

here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.

So the displacement in vertical direction is given as

$\delta y = -25 m$

$\delta y = v_y * t + \frac{1}{2} at^2$

$-25 = 7.25 * t - \frac{1}{2}*9.8* t^2$

by solving above equation we have

$t = 3.12 s$

Now in the above interval of time the horizontal distance moved by it is given by

$d_x = v_x * t$

$d_x = 27.04 * 3.12 = 84.4 m$

since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.

5 0

3 years ago