The value of interest plug in the equation for calculating loan's effective interest rate is 0.085. Thus, option C is correct.
The loan effective interest rate has been given as the rate that has been effectively charged on the principal amount. In the calculation of the interest, the percentage sign has not been considered.
Thus, the interest rate has been converted to the values by dividing the percent to 100.
The effective interest rate (<em>EIR</em>) for the equation has been:
The given interest rate has been 8.5 % . The value plug in the equation has been,
The value of interest plug in the equation for calculating loan's effective interest rate is 0.085. Thus, option C is correct.
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Answer:
Igneous rocks do not contain any fossils.
Explanation:
This is because any fossils in the original rock will have melted when the rock melted to form magma. Sedimentary rocks are formed from the broken remains of other rocks that become joined together.
Answer:
by taking your time in order to collect data
Explanation:
The empirical formula of the compound containing 0.64 g of copper, 0.32 g of sulphur and 0.64 g of oxygen is CuSO₄
From the question given above, the following data were obtained:
Mass of Cu = 0.64 g
Mass S = 0.32 g
Mass of O = 0.64 g
<h3>Empirical formula =? </h3>
The empirical formula of the compound can be obtained as follow:
Cu = 0.64 g
S= 0.32 g
O = 0.64 g
Divide by their molar mass
Cu = 0.64 / 63.5 = 0.01
S= 0.32 / 32 = 0.01
O = 0.64 / 16 = 0.04
Divide by the smallest
Cu = 0.01 / 0.01 = 1
S= 0.01 / 0.01 = 1
O = 0.04 / 0.01 = 4
Therefore, the empirical formula of the compound is CuSO₄
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