Which example is most likely an inorganic compound?

Substances can be categorised in two ways: as an element, mixture or compound ora as a solid, liquid or gas. which

adoni [48]

Answer:

Most substances on earth are compounds and most interesting chemistry is done with compounds. Most interesting chemistry is done with mixtures of compounds although they often start with pure compounds and then do reactions as mixtures. Most chemistry is carried out in liquid solutions made up of compounds that are solids, liquids, or gases in their pure form.

Explanation:

6 0

3 years ago

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Which part of the electrochemical cell allows the back-and-forth passage of ions from the cathode to the anode? the half cell

olganol [36]

Answer is "The salt Bridge"

Explanation:
During the spontaneous reaction in Voltaic Cell, the balance of ions get disturb due to increase in concentration of negative charge in one half cell and positive charge in another. In order to keep balance the charges in cell, concentration of ions on both sides and overall neutrality of the system, a U-shape tube filled with inert electrolyte is connected to both half cells. The electrolyte migrates in such a way that the charges of solution in cells keep constant.

6 0

3 years ago

For each of the following pairs of substances, determine which has the larger molar entropy at 298 K: (A) Br₂(l) or (B) Cl₂(g) (

irakobra [83]

Explanation:

Entropy is defined as the degree of randomness present in a substance. Therefore, more is the irregularity present in a compound more will be its molar entropy.

Hence, decreasing order to molar entropy in state of matter is as follows.

Gases > Liquids > Solids

In the first pair, we are given $Br_{2}(l)$ or $Cl_{2}(g)$ . Since, molar entropy of liquids is less than the molar entropy of gases.

Hence, $Cl_{2}(g)$ will have larger molar entropy as compared to $Br_{2}(l)$ .

In the second pair, we are given Fe(s) or Ni(s). More is the molar mass of a compound more will its molar entropy. Molar mass of Fe is 55.84 g/mol and molar mass of Ni is 58.69 g/mol.

Hence, molar entropy of Ni(s) is more than the molar entropy of Fe(s).

In the third pair, we are given $C_{2}H_{6}(g)$ or $C_{2}H_{4}(g)$ . As both the given species are gaseous in nature. So, more is the molar mass of specie more will be its molar entropy.

Molar mass of $C_{2}H_{6}(g)$ is 30.07 g/mol and molar mass of $C_{2}H_{4}(g)$ is 28.05 g/mol. Therefore, molar entropy of $C_{2}H_{6}(g)$ is more than the molar entropy of $C_{2}H_{4}(g)$ .

In the fourth pair, we are given $CCl_{4}(g)$ or $CH_{4}(g)$ . Molar mass of $CCl_{4}(g)$ is 153.82 g/mol and molar mass of $CH_{4}(g)$ is 16.04 g/mol.

Therefore, molar entropy of $CCl_{4}(g)$ is more than the molar entropy of $CH_{4}(g)$ .

In the fifth pair, we are given HgO(s) or MgO(s). Molar mass of HgO is 216.59 g/mol and molar mass of MgO is 40.30 g/mol.

Hence, molar entropy of HgO(s) is more than the molar entropy of MgO.

In the fifth pair, we are given NaCl(aq) or $MgCl_{2}(aq)$ . Molar mass of NaCl 58.44 g/mol and molar mass of $MgCl_{2}(aq)$ is 95.21 g/mol.

Hence, the molar entropy of $MgCl_{2}(aq)$ is more than the molar entropy of NaCl(aq).

5 0

3 years ago

Which of the following could be considered a scientific statement? (1 point)

KATRIN_1 [288]

The answer to this question is option B. (I observed that butterflies prefer the yellow flowers.) The others are simply just opinions. Give me brainliest please :)

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4 years ago

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HELP!! Suppose that the pressure of 1.00 L of gas is 380 mm Hg when the temperature is 200. K. At what

Korolek [52]

Numa máquina térmica uma parte da energia térmica fornecida ao sistema(Q1) é transformada em trabalho mecânico (τ) e o restante (Q2) é dissipado, perdido para o ambiente.

sendo:

τ: trabalho realizado (J) [Joule]
Q1: energia fornecida (J)
Q2: energia dissipada (J)

temos: τ = Q1 - Q2

O rendimento (η) é a razão do trabalho realizado pela energia fornecida:

η= τ/Q1

Exercícior resolvido:
Uma máquina térmica cíclica recebe 5000 J de calor de uma fonte quente e realiza trabalho de 3500 J. Calcule o rendimento dessa máquina térmica.

solução:

τ=3500 J
Q1=5000J

η= τ/Q1
η= 3500/5000
η= 0,7 ou seja 70%

Energia dissipada será:

τ = Q1 - Q2
Q2 = Q1- τ

Q2=5000-3500
Q2= 1500 J

Exercicio: Qual seria o rendimento se a máquina do exercicio anterior realizasse 4000J de trabalho com a mesma quantidade de calor fornecida ? Quanta energia seria dissipada agora?

obs: Entregar foto da resolução ou o cálculo passo a passo na mensagem

4 0

3 years ago